Answer:
560 m
Explanation:
The speed of sound in air is approximately:
v ≈ v₀ + 0.6T
where v₀ is the speed of sound at 0°C (273 K) in m/s, and T is the temperature in Celsius.
The speed of sound at 20°C at that altitude is:
v ≈ 327 + 0.6(20)
v ≈ 339 m/s
The sound travels from the hikers to the mountain and back again, so it travels twice the distance.
339 m/s = 2d / 3.3 s
2d = 1118.7 m
d = 559.35 m
Rounding, the mountain is approximately 560 m away.
Answer:
option A
Explanation:
given,
travel distance = 1 mm
diffusion constant for the molecule of oxygen in water = 1 x 10⁻⁹ m²/s
we know that

t is the time taken for diffusion
x = 1 mm = 10⁻³ m
D is the diffusion


t = 500 s
so, the option to the answer is 170 s
the correct answer is option A
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I need to force in order to answer. What is it
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You have quoted the law quite accurately but also incompletely.
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