Answer: A group 1 alkali metal bonded to fluoride, such as LiF.
Explanation:
Electronegativity is defined as the property of an element to attract a shared pair of electron towards itself. The size of an atom increases as we move down the group because a new shell is added and electron gets added up.
1. A strong acid made of hydrogen and a halogen, such as HCl : A polar covalent bond is defined as the bond which is formed when there is a difference of electronegativities between the atoms. Electronegativity difference = electronegativity of chlorine - electronegativity of hydrogen = 3-2.1= 0.9
2. A group 1 alkali metal bonded to fluoride, such as LiF: Ionic bond is formed when there is complete transfer of electron from a highly electropositive metal to a highly electronegative non metal.
Electronegativity difference = electronegativity of fluorine - electronegativity of lithium= 4-1= 3
3. Carbon bonded to a group 6A (16) nonmetal chalcogen, such as in CO: A polar covalent bond is defined as the bond which is formed when there is a difference of electronegativities between the atoms.
Electronegativity difference = electronegativity of oxygen - electronegativity of carbon= 3.5-2.5= 1.0
4. A diatomic gas, such as nitrogen
: Non-polar covalent bond is defined as the bond which is formed when there is no difference of electronegativities between the atoms.
Electronegativity difference = 0
Thus the greatest electronegativity difference between the bonded atoms is in LiF.
Answer:
2.41 M
Explanation:
The molarity is the moles of FeCl3 over the liters of solution. Since you're given mL you need to change it to L which is 0.12 L. 0.289 divided by 0.12 is your answer
Heating the solid is the answer
Answer:
The pH is 4.76
Explanation:
Step 1: Data given
Volume of a 0.476 M hydrocyanic acid solution = 29.8 mL = 0.0298 L
Volume of 0.487 M barium hydroxide solution = ?
Ka HCN = 6.2 * 10^-10
Step 2: Calculate pH
Hydrocyanic acid is a weak acid.
Barium hydroxide is a strong base.
The question asked = the pH BEFORE any base has been added, so we can ignore the base.
To calculate the pH of aweak acid, we need the pKa
HCN ⇔ H+ + CN-
Ka = [H+][CN-]/[HCN]
⇒ for weak acid: [H+]=[CN-]
Ka = [H+]²/[HCN]
[H+]² = [HCN]*Ka
[H+] = √([HCN]*Ka)
pH = -log(√([HCN]*Ka))
pH = -log(√(0.476 * 6.2*10^-10))
pH = 4.76
The pH is 4.76