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BARSIC [14]
3 years ago
9

Im gonna ride it do it just how you like it and after that let's do it?

Chemistry
2 answers:
Reika [66]3 years ago
7 0

Answer:

the hell?

Explanation:

Liono4ka [1.6K]3 years ago
4 0
Dababy............................
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Which of the following does NOT involve a change of state? a. pouring water into a vacuum-insulated bottle b. sublimation of dry
Elena L [17]
<h2> The correct option is (a).</h2>

Explanation:

  • There is no change of state in pouring water into a vacuum insulated bottle as the vacuum created inside the bottle only reduces the time limit for the transfer of heat by conduction and convection.
  • It helps the content filled in the bottle to be hot and cool for a longer time.

Hence, option (a) is correct.

Rest of the options (b), (c), (d), (e) is not correct because of the following reasons:

  • In the sublimation of dry ice, the dry ice (solid-state) is changed to the vapour form.
  • In the freezing of water, the liquid state is changed to solid-state.
  • During the vaporization of alcohol, the liquid state is changed to the vapour form.
  • During the melting of ice, the solid-state is changed to the liquid state.

6 0
4 years ago
Which organ is found in the excretory system?
Lemur [1.5K]

Answer:

urethra

Explanation:

6 0
3 years ago
Wetlands provide habitats for many living things because of their sheltered waters and
777dan777 [17]
The choices can be found elsewhere and as follows:

<span>a. large supply of nutrients.
b. thick layer of mud.
c. lack of insects
d. ability to prevent floods.
</span>
I believe the correct answer is option A. Wetlands provide habitats for many living things because of their sheltered waters and large supply of nutrients. Hope this answers the question.
7 0
3 years ago
Read 2 more answers
Answer this i boot you
noname [10]

Answer: answer what

Explanation:

7 0
3 years ago
The value of ka for nitrous acid (hno2) at 25 ∘c is 4.5×10−4. what is the value of δg at 25 ∘c when [h+] = 5.9×10−2m , [no2-] =
LuckyWell [14K]
To get the value of ΔG we need to get first the value of ΔG°:

when ΔG° = - R*T*㏑K

when R is constant in KJ = 0.00831 KJ

T is the temperature in Kelvin = 25+273 = 298 K

and K is the equilibrium constant = 4.5 x 10^-4

so by substitution:

∴ ΔG° = - 0.00831 * 298 K * ㏑4.5 x 10^-4

        = -19 KJ

then, we can now get the value of ΔG when:

ΔG = ΔG° - RT*㏑[HNO2]/[H+][NO2]

when ΔG° = -19 KJ

and R is constant in KJ = 0.00831 

and T is the temperature in Kelvin = 298 K

and [HNO2] = 0.21 m & [H+] = 5.9 x 10^-2 & [NO2-] = 6.3 x 10^-4 m  

so, by substitution:

ΔG = -19 KJ - 0.00831 * 298K* ㏑(0.21/5.9x10^-2*6.3 x10^-4 )

       = -40

     
8 0
3 years ago
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