A measure of how much work we can get from each unit of energy. It's also important because we don't want to kill plants.
Atomic number of O= 8
Atomic number of F = 9
Electron configurations:
⁸O = 1s² 2s² 2p⁴
⁹F = 1s² 2s² 2p⁵
Total electrons: 8+ 9 = 17
For OF the molecular electron configuration would be:
OF = (1σ)²(1σ*)²(2σ)²(2σ*)²(2pσ)²(2pπ)⁴(2pπ*)³
OF⁺ suggests a loss of one electron from the 2pπ* orbital leaving the configuration as:
OF⁺ = (1σ)²(1σ*)²(2σ)²(2σ*)²(2pσ)²(2pπ)⁴(2pπ*)²
Thus, based on MO theory there are two unpaired electrons in OF⁺ ion
Option 2 is the correct answer
Explanation:
The balanced reaction equation is as follows.
As it is given that 2.3 times the amount of 
is needed to drive this reaction we can calculate just how much we have, keeping in mind we only need 5 moles of
.
Hence, 
= 11.5 moles of
= 12 (moles approx)
Therefore, it means that 
is our limiting reagent, so product formed will be as follows.
: 
= 1:4 meaning we create 4 moles of
: 
= 1:3 meaning we create 3 moles of 
As, in the given reaction we had 12 moles of , but 5 moles were consumed in the reaction meaning we have:
12 - 5 = 7 moles of
Thus, we will add up all the moles and get the ratios for each gas as follows.
7 + 4 + 3 = 14 moles
![O_{2} = \frac{7}{14} = 0.5 [tex]H_{2}O = \frac{4}{14}](https://tex.z-dn.net/?f=O_%7B2%7D%20%3D%20%5Cfrac%7B7%7D%7B14%7D%20%3D%200.5%0A%3C%2Fp%3E%3Cp%3E%20%20%20%5Btex%5DH_%7B2%7DO%20%3D%20%5Cfrac%7B4%7D%7B14%7D)
= 0.285
= 0.214
Hence, will be consumed completely.
