Answer:
The magnitude of the force will decrease
Explanation:
The gravitational force is one of the four fundamental forces of nature. It is an attractive force exerted between every object having mass.
Its magnitude is given by the equation:

where
G is the gravitational constant
m1 is the mass of the first object
m2 is the mass of the second object
r is the separation between the objects
As we see from the equation, the magnitude of the gravitational force is inversely proportional to the square of the distance between the objects:

Therefore, this means that as the distance between two bodies increases, the gravitational force will decrease.
Answer:
The the analysis for the free fall part should be done under the constant acceleration.
Explanation:
In the given problem, the jumper is falling under the free fall. Since, no external force is acting on the body therefore, the fall will be under the action gravity only. also, the acceleration due to gravity is always constant.
Therefore, the the analysis for the free fall part should be done under the constant acceleration.
The total momentum should come out to be <span>2.0 x 10^4 kilogram meters/second </span>
The average kinetic energy of a gas particle is directly proportional to the temperature. An increase in temperature increases the speed in which the gas molecules move. All gases at a given temperature have the same average kinetic energy. Lighter gas molecules move faster than heavier molecules.
Answer:
Explanation:
Total length of the wire is 29 m.
Let the length of one piece is d and of another piece is 29 - d.
Let d is used to make a square.
And 29 - d is used to make an equilateral triangle.
(a)
Area of square = d²
Area of equilateral triangle = √3(29 - d)²/4
Total area,

Differentiate both sides with respect to d.

For maxima and minima, dA/dt = 0
d = 8.76 m
Differentiate again we get the

(a) So, the area is maximum when the side of square is 29 m
(b) so, the area is minimum when the side of square is 8.76 m