When an object is moving around in circles, there are two forces that keeps it in its circular orbit. These are the centripetal and the centrifugal forces. They are equal in magnitude, but they differ in the direction. The centripetal force is the force that pulls the object toward the circle's center. The centrifugal force is the force that pushed the object away from the circle's center.
Applying Newton's Second Law of Motions, any force is equal to its mass times its acceleration. For an object moving in circles, the force here is centrifugal or centripetal force, and the acceleration is the centripetal or centrifugal acceleration which is equal to
a = v²/r,
where v is the linear or tangential velocity
r is the radius of the circle
Applying this to Newton's Second Law of Motion,
F = mv²/r
Substituting the values,
F = (1,520 kg)(24 m/s)²/455 m
F = 1,924.22 N
Answer:
6.34 x 19^14 Hz
Explanation:
Wavelength, λ = 473 nm = 473 x 10^-9 m
the relation between the frequency and the wavelength is given by
v = f x λ
where, v is the velocity of light in vacuum which is equal to 3 x 10^8 m/s.
So, f = v / λ
f = ( 3 x 10^8) / ( 473 x 10^-9)
f = 6.34 x 19^14 Hz
Answer:
The fulcrum of the metre stick is at the 40 cm mark
100 g * 10 cm = 1000 g-cm clockwise torque
x * 30 cm = 1000 gm-cm = counterclockwise torque for balance
X = 1000 / (40 -10) = 1000 / 30 = 33.3 gm at 10 cm to balance
Answer:
6logs
Explanation:f
First finding the volume of the logs
V= π/4d²l
= 0.098m³
So number of logs will be
Weight of 2 boys + weight of log = buoyancy force.
So
2( 400)+ N ( Mlog x g) = density of water x volume displaced x g
2(400) = N x 0.098x 1000x 9.8 x 0.9- 0.75* 1000
N= 5.5 which is approx 6logs
