All categories

2 years ago

Pls help me… I missed the whole lesson and I have no clue what to do-

Physics

1 answer:

galben [10]2 years ago

8 0

Answer:

1) 50 facing towards the right

2) 150 facing right

3) 200 facing right

4) 0- no direction

5) 50- facing left

6) 50 facing right

Explanation:

forces in opposite directions and equal magnitudes counteract each other. in number 2 they face the same direction so they would just be added. in number 4 they oppose each other so would be subtracted

You might be interested in

What type of local wind would you experience if you were standing in the valley? Explain your answer.

Stells [14]

Less wind because of the moutians

5 0

2 years ago

Find the magnitude of the force at point x = 15cm if k=10500 N/m when the work done by this force is WD= 1/2k x2

Ann [662]

Answer:

sqdqk3

Explanation:

qdjqưbdkq ưqdhud j

6 0

2 years ago

A 0.15-m straight wire moves with a constant velocity of 7.0 m/s perpendicularly

lana66690 [7]

Answer: force is 0.42 N

Explanation: F = l·v·B

8 0

2 years ago

A pool ball moving 1.33 m/s strikes an identical ball at rest. Afterward, the first ball moves 0.750 m/s at a 33.30 angle. What

kramer

Explanation:

We need to apply the conservation law of linear momentum to two dimensions:

Let $p_{1}$ = momentum of the 1st ball

$p_{2}$ = momentum of the 2nd ball

In the x-axis, the conservation law can be written as

$(p_{1} \cos \theta_{1})_{i} + (p_{2} \cos \theta_{2})_{i} = (p_{1} \cos \theta_{1})_{f} + (p_{2} \cos \theta_{2})_{f}$

$(m_{1}v_{1})_{i}= (m_{1}v_{1}\cos \theta_{1})_{f} + (m_{2}v_{2}\cos \theta_{2})_{f}$

Since we are dealing with identical balls, all the m terms cancel out so we are left with

$(v_{1})_{i} = (v_{1})_{f}\cos \theta_{1} + (v_{2})_{f}\cos \theta_{2}$

Putting in the numbers, we get

$1.33 = (0.750) \cos(33.30) + (v_{2})_{f} \cos \theta_{2}$

$= > (v_{2})_{f} \cos \theta_{2} = 0.703$

In the y-axis, there is no initial y-component of the momentum before the collision so we can write

$0 = (v_{1}\sin \theta_{1})_{f} + (v_{2}\sin \theta_{2})_{f}$

$= > (v_{2})_{f} \sin \theta_{2} = (0.750) \sin(33.30) = 0.412$

Taking the ratio of the sine equation to the cosine equation, we get

$\frac{ \sin \theta _{2}}{ \cos \theta_{2} } = \tan \theta_{2} = \frac{0.412}{0.703} = 0.586$

$\theta_{2} = { \tan}^{ - 1} (0.586) = 30.4$

Solving now for $(v_{2})_{f}$ ,

$(v_{2})_{f} = \frac{0.412}{ \sin(30.4) } = 0.815 \: \frac{m}{s}$

3 0

2 years ago

Can you explain how population changes in size

geniusboy [140]

Answer:

The population growth rate is the rate at which the population changes in size.

Explanation:

The rate of change is determined by subtracting the number of people that leave the population, through death or emigration, from the number of individuals that enter the population, through birth or immigration.

7 0

3 years ago