Answer:
The answer to your question is 720.5°K
Explanation:
Data
Volume 1 = 285 ml
Temperature 1 = 355 °K
Pressure 1 = 1.88 atm
Volume 2 = 435 ml
Temperature 2 = ?
Pressure 2 = 2.5 atm
Formula
To solve this problem use the combined gas law
P1V1 / T1 = P2V2 / T2
- Solve for T2
T2 = T1P2V2 / P1V1
- Substitution
T2 = (355)(2.5)(435) / (1.88)(285)
- Simplification
T2 = 386062.5 / 535.8
- Result
T2 = 720.53°K
Conclusion
The gas must be heated to 720.5°K
We know, a = v/t
Here, a = 5 m/s²
v = 50 km/h= 13.88 m/s
Substitute their values into the expression:
5 = 13.88 / t
t = 13.88/5
t = 2.78 sec
Now, we know, v = d/t
13.88 = d/2.78
d = 13.88 * 2.78
d = 38.53 meter
In short, Your Answers would be:
i) It will take 2.78 sec
ii) It will travel for 38.53 m after a brakes applied.
Hope this helps!
Potential energy at any point is (M G H). On the way down, only H changes. So halfway down, half of the potential energy remains, and the other half has turned to kinetic energy. Half of the (M G H) it had at the tpp is (0.5 x 9.8 x 10) = 49 joules.
5 km / 2 hrs
= (5/2) (km/hr)
= 2.5 km/hr .
