Explanation:
An perfect mass less spring, attached at one end and with a free mass attached at the other end, will have a distinct frequency of oscillation depending on its constant spring and mass. On the other hand, a spring with mass along its length will not have a characteristic frequency of oscillation.
Alternatively, based on its spring constant and mass per length, it will now have a wave Speed. It would be possible to use all wavelengths and frequencies, as long as the component fλ= S, where S is the spring wave size. If that sounds like longitudinal waves, like solid sound waves.
Answer:
d) -4.0
Explanation:
The magnification of a lens is given by

where
M is the magnification
q is the distance of the image from the lens
p is the distance of the object from the lens
In this problem, we have
p = 50 cm is the distance of the object from the lens
q = 250 cm - 50 cm is the distance of the image from the lens (because the image is 250 cm from the obejct
Also, q is positive since the image is real
So, the magnification is

So, the angle between two vectors having equal magnitude is equal to 120º.
Explanation:
<h2>:) Correct me if I'm wrong...</h2>
Answer:
The wavelength in miles is <u>0.1165 miles</u>.
Explanation:
Given:
Wavelength of the radio wave is 187.37 m.
Now, the wavelength is given in meters.
We need to convert the wavelength from meters to miles.
In order to convert meters to miles, we have to use their conversion factor.
We know that,
1 meter = 
Therefore, the conversion factor is given as:

So, the wavelength in miles is given as:

Hence, the wavelength in miles is 0.1165 miles.
Your answer is- amplitudes