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S_A_V [24]
3 years ago
11

An oil slick on water is 120 nm thick and illuminated by white light incident perpendicular to its surface. What color does the

oil appear (what is the most constructively reflected wavelength), given its index of refraction is 1.40?
Physics
1 answer:
gregori [183]3 years ago
8 0

Answer:

\lambda = 672 nm

so this is nearly red colour light

Explanation:

As we know that the interference of light from reflected light then the path difference is given as

\Delta x = 2\mu t + \frac{\lambda}{2}

now we know that for constructive interference of light the path difference is given as

\Delta x = n\lambda

so we will have

2\mu t + \frac{\lambda}{2} = N\lambda

so we will have

4\mu t = \lambda

\lambda = 2(1.40)(120nm)

\lambda = 672 nm

so this is nearly red colour light

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For a two-level system, the weight of a given energy distribution can be expressed in terms of the number of systems, N, and the
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Answer:

W = N!/(n0! * n1!)

Explanation:

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Coherent microwaves of wavelength 5.00 cm enter a tall, narrow window in a building otherwise essentially opaque to the microwav
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The solution for this problem is:

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8 0
3 years ago
A 20.0-N weight slides down a rough inclined plane which makes an angle of 30 degree with the horizontal. The weight starts from
Ulleksa [173]

Answer:

1270.64\ \text{J}

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v = Final velocity = 15 m/s

u = Initial velocity = 0

d = Distance moved by the object = 150 m

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f = Force of friction

fd = Work done against friction

The force balance of the system is

\dfrac{1}{2}m(v^2-u^2)=(mg\sin\theta-f)d\\\Rightarrow \dfrac{1}{2}mv^2=mg\sin\theta d-fd\\\Rightarrow fd=mg\sin\theta d-\dfrac{1}{2}mv^2\\\Rightarrow fd=20\times \sin 30^{\circ}\times 150-\dfrac{1}{2}\times \dfrac{20}{9.81}\times 15^2\\\Rightarrow fd=1270.64\ \text{J}

The work done against friction is 1270.64\ \text{J}.

8 0
3 years ago
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