The solubility constant or Ksp is calculated by the product of the concentration of the ions raise to the stoichiometric coefficient. We calculate as follows:
BaCrO4 = Ba2+ + CrO42-
Ksp = [Ba2+][CrO4]
Ksp = [1.08×10−5<span> ] [1.08×10−5] = 1.1664x10^-10</span>
M (NaCl) = n × M = 3.75 × 58.5 =
219.375 g
M (NaCl) = 23 + 35.5 = 58.5 g/mol
Answer:
42.8
Explanation:
A particle travelling through potential difference V has energy E =qV = 1/2mv²
v = √(2qV / m)
ve = √(2qV / me)
vh = √(2qV / mh)
ve / vh = √( (2qV / me) ÷(2qV / mh) = √ ( mh / me ) where mh = mass of hydrogen ion and me is mass of electron, V voltage is the same, ve is speed of electron and vh is the speed of hydrogen ion
ve / vh = √ ( mh / me ) = √ ( 1.67 × 10⁻²⁷ kg) / ( 9.11 × 10 ⁻³¹ kg) = 42.8
Answer : The volume in mL of the sodium carbonate stock solution is 364 mL.
Explanation :
According to dilution law:
where,
= molarity of aqueous sodium carbonate
= molarity of aqueous sodium carbonate stock solution
= volume of aqueous sodium carbonate
= volume of aqueous sodium carbonate stock solution
Given:
= 1.00 M
= 1.58 M
= 575 mL
= ?
Now put all the given values in the above formula, we get:
Therefore, the volume in mL of the sodium carbonate stock solution is 364 mL.
