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LiRa [457]
4 years ago
10

Help please .............​

Chemistry
1 answer:
lapo4ka [179]4 years ago
3 0

Answer:

And what is your question

Explanation:

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Marcus wants to use two objects to compare the sizes of a proton and an electron. If he uses a basketball for a proton, which ob
ra1l [238]

Answer:

A

Explanation:

3 0
3 years ago
For an exothermic reaction, what effect will increasing the temperature have on equilibrium?
Dmitrij [34]
The system will then shift to the left, making more reactants.
6 0
3 years ago
Read 2 more answers
What is ΔE in kJ for a system that receives 1.79 kJ of heat from surroundings and has 4.51 kcal of work done on it at the same t
kenny6666 [7]

Answer: 20.7 kJ

Explanation:

According to first law of thermodynamics:

\Delta E=q+w

\Delta E=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done on the system=-P\Delta V  {Work is done on the system is positive as the final volume is lesser than initial volume}

w = 4.51 kcal = 4.51\times 4.184kJ=18.9kJ    (1kcal = 4.184kJ)

q = +1.79 kJ   {Heat absorbed by the system is positive}

\Delta E=+1.79+(18.9)=20.7kJ

Thus \Delta E for a system that receives 1.79 kJ of heat from surroundings and has 4.51 kcal of work done on it at the same time is 20.7 kJ

4 0
3 years ago
Gas
Eduardwww [97]

Answer:

844.4cm³

Explanation:

Using Boyle's law equation;

P1V1 = P2V2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

V1 = initial volume (cm³)

V2 = final volume (cm³)

According to the information in this question,

V1 = 650cm³

P1 = 760mmHg

P2 = ?

V2 = 10% reduction of V1

10% of 650 = 10/100 × 650

65

V2 = 650 - 65 = 585cm³

Using P1V1 = P2V2

P2 = P1V1 ÷ V2

P2 = (760 × 650) ÷ 585

P2 = 494000 ÷ 585

P2 = 844.44

final pressure (P2) = 844.4cm³

4 0
3 years ago
What are some factors that affect weather?
Zarrin [17]
B is the right answer
6 0
3 years ago
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