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Kitty [74]
3 years ago
9

Help please hurry! ‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️

Physics
1 answer:
eimsori [14]3 years ago
8 0
IV - Temperature
DV - Light intensity
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in a circuit with two resistors in parallel, which of the following pair applies? a. V and I both increase across both resistors
makvit [3.9K]

The wording of the choices is really unclear.  With two resistors in parallel,
here's the situation:

-- The voltage across each resistor is the same as the voltage across
the other one.  If the parallel combination is connected to the battery,
then the voltage across each resistor is the full battery voltage.

-- The current through each resistor is (V) / (the resistance of that resistor).
That's the same current as would flow through that resistor if the other one
were not there.

-- As long as the battery or other power supply holds out, neither of these
quantities changes.

Can you match this situation to one of the choices listed ?
It looks to me as if choice 'C' is the one that's most likely
trying to say this.


6 0
4 years ago
A particle of mass 7.00 10-8 kg and charge 7.8-µc is traveling due east. it enters perpendicularly a magnetic field whose magnit
sertanlavr [38]
The radial force on the particle is given by the Lorentz force.  They don't give you the velocity so you have to solve for it in terms of the radius and get them to cancel.

6 0
3 years ago
How much time does it take the cheetah to travel 500 meters, if its average speed is 70 meters per second?
Whitepunk [10]

Answer: 7.14

Explanation:

6 0
3 years ago
Which quantity is a vector quantity A. Acceleration B. Mass C. Speed D. Volume
Marianna [84]

Answer:

Acceleration

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5 0
3 years ago
In a physics laboratory experiment, a coil with 200 turns enclosing an area of 13.1 cm2 is rotated during the time interval 3.10
sergij07 [2.7K]

Answer:

A)\Phi=83.84\times 10^{-9}

B)\Phi=0 Wb

C)emf=5.4090\times 10^{-4}V

Explanation:

Given that:

  • no. of turns i the coil, n=200
  • area of the coil, a=13.1 \times 10^{-4}\,m^2
  • time interval of rotation, t=3.1\times 10^{-2}\,s
  • intensity of magnetic field, B=6.4\times 10^{-5}\,T

(A)

Initially the coil area is perpendicular to the magnetic field.

So, magnetic flux is given as:

\Phi=B.a\,cos \theta..................................(1)

\theta is the angle between the area vector and the magnetic field lines. Area vector is always perpendicular to the area given. In this case area vector is parallel to the magnetic field.

\Phi=6.4\times 10^{-5}\times 13.1 \times 10^{-4}\, cos 0^{\circ}

\Phi=83.84\times 10^{-9} Wb

(B)

In this case the plane area is parallel to the magnetic field i.e. the area vector is perpendicular to the magnetic field.

∴  \theta=90^{\circ}

From eq. (1)

\Phi=6.4\times 10^{-5}\times 13.1 \times 10^{-4}\, cos 90^{\circ}

\Phi=0 Wb

(C)

According to the Faraday's Law we have:

emf=n\frac{B.a}{t}

emf=\frac{200\times 6.4\times 10^{-5}\times 13.1 \times 10^{-4}}{3.1\times 10^{-2}}

emf=5.4090\times 10^{-4}V

7 0
3 years ago
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