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3 years ago

In what layer of the atmosphere does the International Space Station orbit?

Chemistry

1 answer:

Paladinen [302]3 years ago

8 0

Answer:

Explanation:

The thermosphere.

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What is the initial temperature (°C) of a system that has the pressure decreased by 10 times while the volume increased by 5 tim

Ede4ka [16]

Answer:

300K

Explanation:

Given pressure of the system decreased by 10 times which means $P_{2} =\frac{P_{1} }{10}$

Given the volume of the system increased by 5 times which means $V_{2} =5\times V_{1}$

Given final temperature $T_{2}=150K$

Let the initial temperature be $T_{1}$

We know that PV=nRT

As n and R are constant $\frac{PV}{T}=constant$

$\frac{P_{1}V_{1} }{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}$

$T_{1} =\frac{P_1V_1}{P_2V_2} T_{2}$

$T_{1} =2\times T_{2}$

T1=300K

8 0

3 years ago

2-- What is the [H3O+] in a solution with [OH-] = 1 x 10-12 M?

Arte-miy333 [17]

Answer:

The answer is 0.01 M

Explanation:

The problem is solved by applying the expression for ionic product of water as follows:

Kw = [H₃O⁺] [OH⁻]

Where Kw is the ionic product of water and it is 1.10⁻¹⁴ M at⁴ 25ºC. As [OH⁻]= 1.10⁻¹² M, [H₃O⁺] will be:

[H₃O⁺]= Kw/ [OH⁻]= 1.10⁻¹⁴M/1.10⁻¹²M= 0.01 M

5 0

3 years ago

If helium had exactly the same mass as four hydrogen atoms, the luminosity o f the sun would be

Katena32 [7]

Hydrogen has an atomic mass of about 1 and It contains one proton, orbited by a single electron. Helium has an atomic mass of approximately 4 and contains of 2 protons and 2 neutrons, orbited by 4 electrons. But all of this is irrelevant because luminosity is related to gravity, and that mass would identical, luminosity would be near identical. *insert luminosity relation equation here*

7 0

3 years ago

Plz help and plz tell me if u need any thing else

andrew-mc [135]

Pick "A" as the answer.

4 0

4 years ago

A sulfuric acid solution containing 571.6 g of H2SO4 per liter of solution has a density of 1.329 g/cm3. Calculate (a) the mass

IgorLugansk [536]

Answer:

a) 43%

b) 0.122

c) 7.70 molal

d) 5.83 M

Explanation:

Step 1: Data given

Mass of H2SO4 = 571.6 grams

Density of H2SO4 = 1.329 g/cm³ this means 1.329 grams per 1 mL or 1329 grams per 1L

a) Calculate mass percentage

Mass % = (571.6 grams / 1329 grams)* 100% = 43%

b) Calculate mole fraction

Number of moles H2SO4 = Mass H2SO4 / Molar mass H2SO4

Moles H2SO4 = 571.6 grams / 98.08 g/mol

Moles H2SO4 = 5.83 moles

Moles H2O = (1329 -571.6)/18.02 = 42.03 moles

Total moles = 5.83 + 42.03 = 47.86 moles

Mole fraction H2SO4 = Moles of solute (H2SO4)/ Total moles

Mole fraction H2SO4 = 5.83 moles / 47.86 moles

Mol fraction h2SO4 = 0.122

c) Calculate the molality

Mass of solvent = 1329 grams - 571.6 grams = 757.4 grams = 0.7574 kg

Molality of H2SO4 = number of moles H2SO4 / mass of solvent

Molality H2SO4 = 5.83 moles / 0.7574 kg

Molality H2SO4 = 7.70 molal

d) Calculate Molarity

Molarity H2SO4 = Number of moles H2SO4 / volume

Molarity H2SO4 = 5.83 moles / 1L = 5.83 M

6 0

3 years ago