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wolverine [178]
3 years ago
10

In 3 meters a person running 0.5 m/s accelerates 1.2 m/s 2. How fast were they going afterward? Choose the right equation for th

is word problem from below.
Physics
1 answer:
Feliz [49]3 years ago
7 0

Answer:

2.72 m/s

Explanation:

In 3 meters a person running 0.5 m/s accelerates 1.2 m/s².

It means,

Distance, s = 3 m

Initial velocity, u = 0.5 m/s

Acceleration, a = 1.2 m/s²

We need to find the final velocity of the person. Using equation of motion to find it as follows :

v^2-u^2=2as\\\\v^2=2as+u^2\\\\v^2=2\times 1.2\times 3+(0.5)^2\\\\v=2.72\ m/s

So, the final velocity of the person is 2.72 m/s.

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Answer:

Option C, The total momentum of the fragments is equal to the original momentum of the firecracker.

Explanation:

Kinetic energy of cracker cannot remain constant before and after explosion. It is so because in the process of burning and bursting some amount of kinetic energy is lost in the form of light and heat energy. While the total mass before and after the explosion remains constant due to which the momentum is conserved before and after the explosion

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Explanation:

The Net Force of the object can be written by:

Fnet = ma

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Fnet = (2.0)(3.0)

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Phyllis is calculating the path of a space probe that will travel to Pluto. On the way to Pluto, the probe will pass Mars, Satur
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Find the interest. A 105-day note for $14,200 at 8.5% interest.
mr Goodwill [35]
<h3><u>Answer</u>;</h3>

$347.22

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Time = 105 days = 105/365

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