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3 years ago

7. How much ice is left over if 46 kJ of energy is added to 175 g of ice?

Chemistry

1 answer:

velikii [3]3 years ago

6 0

Answer:

$m_{leftover}=37g$

Explanation:

Hello!

In this case, since the melting process involves the heat added to the system, the heat of fusion and the mass of water:

$Q=m\Delta H_{fus}$

Thus, as it has been reported that the heat of fusion of ice is 333.6 J/g, we can compute the melted mass of ice as shown below:

$m=\frac{Q}{\Delta H_{fus}} =\frac{46000J}{333.6J/g}\\\\m=138g$

Thus, the ice leftover results:

$m_{leftover}=175g-138g\\\\m_{leftover}=37g$

Regards!

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If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant?

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Answer:

The correct answer is option B.

Explanation:

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Moles of $NBr_3$ = 40 mol

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According to reaction, 3 moles of NaOH reacts with 2 moles $NBr_3$

Then ,48 moles of NaOH will reacts with:

$\frac{2}{3}\times 48 mol=32 mol$ of $NBr_3$

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3 years ago

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Moles of ZnO = 0.0688 moles

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