Question

7. How much ice is left over if 46 kJ of energy is added to 175 g of ice?

Answer 1

Answer:

$m_{leftover}=37g$

Explanation:

Hello!

In this case, since the melting process involves the heat added to the system, the heat of fusion and the mass of water:

$Q=m\Delta H_{fus}$

Thus, as it has been reported that the heat of fusion of ice is 333.6 J/g, we can compute the melted mass of ice as shown below:

$m=\frac{Q}{\Delta H_{fus}} =\frac{46000J}{333.6J/g}\\\\m=138g$

Thus, the ice leftover results:

$m_{leftover}=175g-138g\\\\m_{leftover}=37g$

Regards!