Answer:
U=α/(x+x_0)^2
v=1.88m/s
Explanation:
We have that
![F(x)=\frac{\alpha}{(x+x_0)^2}\\\alpha=0.800Nm^2\\x_0=0.200m](https://tex.z-dn.net/?f=F%28x%29%3D%5Cfrac%7B%5Calpha%7D%7B%28x%2Bx_0%29%5E2%7D%5C%5C%5Calpha%3D0.800Nm%5E2%5C%5Cx_0%3D0.200m)
(a)
The potential is calculated by using
![U=-\int Fdx=-\int \frac{\alpha}{(x+x_0)^2}dx\\U=\frac{\alpha}{(x+x_0)}](https://tex.z-dn.net/?f=U%3D-%5Cint%20Fdx%3D-%5Cint%20%5Cfrac%7B%5Calpha%7D%7B%28x%2Bx_0%29%5E2%7Ddx%5C%5CU%3D%5Cfrac%7B%5Calpha%7D%7B%28x%2Bx_0%29%7D)
(b)
m=0.5kg
The acceleration can be obtained if we calculate the force for x=4, and after we compute the acceleration
![F(0.4)=\frac{0.8Nm^2}{(0.4m+0.2m)^2}=2.22N\\F=ma\\2.22N=(0.5kg)a\\a=4.44\frac{m}{s^2}](https://tex.z-dn.net/?f=F%280.4%29%3D%5Cfrac%7B0.8Nm%5E2%7D%7B%280.4m%2B0.2m%29%5E2%7D%3D2.22N%5C%5CF%3Dma%5C%5C2.22N%3D%280.5kg%29a%5C%5Ca%3D4.44%5Cfrac%7Bm%7D%7Bs%5E2%7D)
and finally, we can use the equation for the final speed
![v^2=v_0^2+2ax\\\\v=\sqrt{(0)+2(4.44\frac{m}{s^2})(0.4m)}\\\\v=1.88\frac{m}{s}](https://tex.z-dn.net/?f=v%5E2%3Dv_0%5E2%2B2ax%5C%5C%5C%5Cv%3D%5Csqrt%7B%280%29%2B2%284.44%5Cfrac%7Bm%7D%7Bs%5E2%7D%29%280.4m%29%7D%5C%5C%5C%5Cv%3D1.88%5Cfrac%7Bm%7D%7Bs%7D)
I hope this is useful for you
regards
Answer:
Farm = 98.1 [N]
Explanation:
To solve this problem we must draw the respective free body diagram, with the forces acting on the monkey. An analysis of the sums on the y-axis must be performed, in this axis the weight is acting down and the forces of both arms pulling up.
Weight is defined as the product of mass by gravitational acceleration.
W = m*g
where:
m = mass = 20 [kg]
g = gravity acceleration = 9.81 [m/s²]
W = 196.2 [N] (units of Newtons)
As this force points down, the force of both arms must go up, therefore each arm exerts a force of:
Farm = 196.2 / 2
Farm = 98.1 [N]
<h2>Frequency of trumpet wire = 445 Hz</h2>
Explanation:
The given frequency of tuning fork is 440 Hz . It produces 5 beats with trumpet wire . That means , the frequency of wire can be 440 ± 5
It can be either 445 or 435
Now the length of wire is increased , by which its frequency decreases . Because frequency is inversely proportional to length of wire .
If we decrease the frequency in 435 , the difference between tuning fork frequency and wire frequency will become greater than 5 even . So it cannot produce 3 beats with it .
If we decrease frequency from 445 , it can become 443 Hz . It gives 3 beat with the tuning fork as given .
Thus the initial frequency of wire is 445 Hz
Answer:
hub moon merc saturn sun galaxy deep field
Explanation:
Answer:2√(2)km Southeast
Explanation:
Displacement=√(2)+√(2)=2√(2)km Southeast