If force decreases, what must happen to distance for work to remain the same?
2 answers:
You might be interested in
assuming north-south along the Y-axis and east-west along the X-axis
X = total X-displacement
from the graph , total displacement along X-direction is given as
X = 0 - 20 + 60 Cos45 + 0
X = 42.42 - 20
X = 22.42 m
Y = total Y- displacement
from the graph , total displacement along Y-direction is given as
Y = 40 + 0 + 60 Sin45 + 50
Y = 90 + 42.42
Y = 132.42 m
magnitude of the net displacement vector using Pythagorean theorem is given as
magnitude : Sqrt(X² + Y²) = Sqrt(22.42² + 132.42²) = 134.31 m
Direction : tan⁻¹(Y/X) = tan⁻¹(132.42/22.42) = 80.4 deg north of east
Answer:
Explanation:
We know that speed is defined as distance moved per unit time hence expressed as where v is speed in m/s, d is distance in m and t is time in seconds. Making d the subject of the above formula then
Substituting 343 m/s for d and 10 s for t then
Therefore, the distance between speaker and deter is
Answer: 25.7m/s
Explanation: the cars have equal masses so we only consider their velocities,
The cars traveled together at 65° north of east this is with a velocity equal to the resultant velocity,
Using the force diagram as shown below;
Tan 65° = Vn/Ve
Ve is velocity of the car traveling east
Vn is velocity of car traveling north
Tan 65° = V2/12
2.144 = V2/12
V2 = 12 * 2.144
V2 = 25.7 m/s
