Answer:
18.76 g of copper II nitrate
Explanation:
Now recall that we must use the formula;
n= CV
Where;
n= number of moles of copper II nitrate solid
C= concentration of copper II nitrate solution
V= volume of copper II nitrate solution
Note that;
n= m/M
Where;
m= mass of solid copper II nitrate
M= molar mass of copper II nitrate
Thus;
m/M= CV
C= 0.05 M
V= 2.00 L
M= 187.56 g/mol
m= the unknown
Substituting values;
m/ 187.56 g/mol = 0.05 M × 2.00 L
m= 0.05 M × 2.00 L × 187.56 g/mol
m= 18.76 g of copper II nitrate
Therefore, 18.76 g of copper II nitrate is required to make 0.05 M solution of copper II nitrate in 2.00 L volume.
A. 3<span> chemical reactions are possible regarding the formation of carbonic acid and the dissolving of calcite.</span>
I think it comes from Fungi. I'm not 100% sure about that though.
Answer:
pH = 11.7
Explanation:
<u>Given:</u>
[OH-] = 0.00500 M
<u>To determine:</u>
pH of the solution
<u>Explanation:</u>
pH refers to the H+ ion concentration in a given solution whereas pOH indicates the OH- ion concentration.
pH and pOH are related by the following equation:

Here:
![pH = -log[H+]\\\\pOH = -log[OH-]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH%2B%5D%5C%5C%5C%5CpOH%20%3D%20-log%5BOH-%5D)
When OH- = 0.00500 M

Based on equation(1):
