Answer:
1.76m/s²
Explanation:
Given parameters:
Initial velocity = 0m/s
Final velocity = 65m/s
Distance traveled = 1200m
Unknown:
Acceleration = ?
Solution:
This is linear velocity and we apply the appropriate motion equation to solve this problem.
V² = U² + 2as
S is the distance
u is the initial velocity
V is the final velocity
a is the acceleration
Now, insert the parameters and solve;
65² = 0² + 2 x a x 1200
4225 = 2400a
a = 1.76m/s²
Answer:
get students and a license
The viscous force on an object moving through air is proportional to its velocity.
The only forces acting on an object when falling are air resistance and its weight itself. The weight acts vertically downwards whereas air resistance acts vertically upward.
Let F be the viscous force due to air molecules, B be buoyant force due to air and W be the weight of falling object. Initially, the velocity of falling object and hence the viscous force F is zero and the object is accelerated due to force
(W-B). Because of the acceleration the velocity increases and accordingly the viscous force also increases. At a certain instant, the viscous force becomes equal to W-B. The net force then becomes zero and the object falls with constant velocity. This constant velocity is called terminal velocity.
Thus at terminal velocity, air resistance and force of gravity becomes equal.
Answer:
Explanation:
Given
mass of box 
speed of box 
distance moved by the box 
coefficient of kinetic friction 
Friction force 
Kinetic Energy of box will be utilize to overcome friction and rest is stored in spring in the form of elastic potential energy
