Answer:
D because excited electrons fall back.....
Answer:
a. 0.5 mol
b. 1.5 mol
c. 0.67
Explanation:
Fe3+ + SCN- -----> [FeSCN]2+
a. The ratio of the product to Fe3+ is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of Fe3+ was used. Leaving 0.5 mol remaining at equilibrium
b. The ratio of the product to SCN= is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of SCN- was used. Leaving 1.5 mol remaining at equilibrium
c. KC = 0.5/(0.5*1.5) = 0.67
Answer:
They all end up in the oceon
Explanation:
Answer:
66.7%
Explanation:
Step 1: Write the balanced equation
CHCl₃ + Cl₂ ⇒ CCl₄ + HCl
Step 2: Calculate the theoretical yield of CCl₄ from 11.9 g of CHCl₃
According to the balanced equation, the mass ratio of CHCl₃ to CCl₄ is 119.38:153.82.
11.9 g CHCl₃ × 153.82 g CCl₄/119.38 g CHCl₃ = 15.3 g CCl₄
Step 3: Calculate the percent yield of CCl₄
Given the experimental yield of CCl₄ is 10.2 g, we can calculate the percent yield using the following expression.
%yield = (exp yield/theo yield) × 100%
%yield = (10.2 g/15.3 g) × 100% = 66.7%
The molar mass of the compound is 68 g/mol.
<h3>What is the molar mass?</h3>
The Osmotic pressure can be obtained from the relationship;
π= iCRT
π= osmotic pressure = 28.1 mmHg or 0.037 atm
i = Vant Hoff factor = 1
C = concentration = ?
R = gas constant = 0.082 atmLK-1Mol
T = temperature = 20°c + 273 = 293 K
C = π/iRT
C = 0.037/1 * 0.082 * 293
C = 0.0015 M
Now;
Number of moles = C/V = 0.0015/100 * 10^-3
= 0.015 moles
Number of moles = mass/molar mass
Molar mass = mass/Number of moles = 0. 102 g/ 0.015 moles = 68 g/mol
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