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Sati [7]
2 years ago
8

What forces are present in this situation?

Chemistry
2 answers:
Andre45 [30]2 years ago
4 0

Answer:

gravity and tension i believe is the answer HOPE THIS HELPED

Explanation:

Deffense [45]2 years ago
4 0
Gravity and tension sound about right
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As the [H+] in a solution decreases, what happens to the [OH–]? A. It increases and the pH increases. B. It increases and the pH
AleksAgata [21]
<h3><u>Answer;</u></h3>

D. It decreases and the pH increases.

<h3><u>Explanation;</u></h3>
  • pH is a measure of the hydorgen ion concentration of a solution. Solutions with a high concentration of hydrogen ions have a low pH and solutions with a low concentrations of H+ ions have a high pH.
  • <em><u>[H+] and [OH-] are inversely related. Therefore; As the concentration of H+ increases the pH decreases. Since the concentrations of H+ and OH- are inversely proportional, as one goes up, the other goes down. </u></em>
  • <em><u>Therefore, an increase in OH- concentration will correspond to an increase in pH and a decrease in the concentration of H+.</u></em>
5 0
3 years ago
Read 2 more answers
If a gas is initially at a pressure of 9 atm, a volume of 21 liters, and a temperature of 253 K, and then the pressure is raised
alex41 [277]

Answer:

15.04 mL

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

V₁ = 21 L

V₂ = ?

P₁ = 9 atm

P₂ = 15 atm

T₁ = 253 K

T₂ = 302 K

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac {{9}\times {21}}{253}=\frac {{15}\times {V_2}}{302}

Solving for V₂ , we get:

<u>V₂ = 15.04 mL</u>

3 0
3 years ago
Please help and show work, i will mark you brainlest
Natali [406]

Answer:

7x-2(3-4)-2

Pls help

Explanation:

8 0
3 years ago
Density of water calculation using a 10 mL graduated cylinder
matrenka [14]

Answer:

Average density of the liquid = 0.992 g/mL

Explanation:

Density = mass/volume

mass of liquid = (mass of liquid + mass of cylinder) - mass of cylinder

Trial 1: mass of liquid = 19.731 - 9.861 = 9.87

volume of liquid = 10 mL

density of liquid = 9.87 g / 10 mL = 0.987 g/mL

Trial 2: mass of liquid = 19.831 - 9.861 = 9.97

volume of liquid = 10 mL

density of liquid = 9.97 g / 10 mL = 0.997 g/mL

Trial 3: mass of liquid = 19.831 - 9.861 = 9.97

volume of liquid = 10 mL

density of liquid = 9.97 g / 10 mL = 0.997 g/mL

Trial 4: mass of liquid = 19.771 - 9.861 = 9.91

volume of liquid = 10 mL

density of liquid = 9.91 g / 10 mL = 0.991 g/mL

Trial 5: mass of liquid = 19.751 - 9.861 = 9.89

volume of liquid = 10 mL

density of liquid = 9.89 g / 10 mL = 0.989 g/mL

Average density = (0.987 + 0.997 + 0.997 + 0.991 + 0.989)/5 = 4.961/5

Average density of the liquid = 0.992 g/mL

8 0
3 years ago
Calculate number of moles present in 2.3g
Natalija [7]

Explanation:

idk if that's the actual answer but I hope it helps (:

4 0
2 years ago
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