The protons of methylene group between the two carbonyl groups in ethylacetoacetate are acidic in nature. When compounds containing such acidic protons are treated with bases the loose proton and form enolates.
In this particular example when ethylacetoacetate is reacted with methyl magnesium bromide, the methyl group abstracts the acidic proton and converts into
methane gas. The enolate when hydrolyzed is again converted into ethylacetoacetate as shown below,
Answer:
volume of gas = 9.1436cm³
Explanation:
We will only temperature from °C to K since the conversion is done by the addition of 273 to the Celsius value.
Its not necessary to convert pressure and volume as their conversions are done by multiplication and upon division using the combined gas equation, the factors used in their conversions will cancel out.
V1 =10.1cm³ , P1 =746mmHg, T1=23°C =23+273=296k
V2 =? , P2 =760mmmHg , T2=0°C = 0+273 =273K
Using the combined gas equation to calculate for V2;
V2=9.1436cm³
Answer:
b. I've seen a question like this before lol
Answer:
In pair NaF and H2O both compounds exibit predominantly ionic bonding.
Answer:
114.7g
Explanation:
Given parameter:
Mass of Na = 45g
Unknown:
Mass of produced NaCl = ?
Solution:
The reaction equation is shown below;
2Na + Cl₂ → 2NaCl
Now, we solve from the known to the unknown. The known here is the mass of Na and it is sufficient to solve the problem;
Number of moles = 
Molar mass of Na = 23g/mol
Number of moles = 
= 1.96moles
2 mole of Na produced 2 moles of NaCl
1.96 moles of Na will produce 1.96 moles of NaCl
Mass of NaCl = number of moles x molar mass
= 1.96 x [23 + 35.5]
= 114.7g
