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Dmitry_Shevchenko [17]
3 years ago
9

A 10.0 mL sample of HNO3 was diluted to a

Chemistry
1 answer:
vivado [14]3 years ago
7 0

Answer:

12 M

Explanation:

The reaction between HNO₃ and KOH is:

  • HNO₃ + KOH → KNO₃ + H₂O

First we <u>calculate how many KOH moles reacted with the diluted HNO₃ sample</u>, using<em> the given volume and concentration</em>:

  • 50.0 mL * 0.60 M = 30 mmol KOH

As 1 KOH mol reacts with 1 HNO₃ mol, in 25 mL of the diluted HNO₃ solution there are 30 HNO₃ mmoles.

With that information in mind we can <u>calculate the HNO₃ concentration in the diluted solution</u>:

  • 30 mmol HNO₃ / 25 mL = 1.2 M

Finally we can<em> use the C₁V₁=C₂V₂ formula</em> to <u>calculate the concentration of the original solution</u>:

  • C₁ * 10.0 mL = 1.2 M * 100.00 mL
  • C₁ = 12 M
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