A 10.0 mL sample of HNO3 was diluted to a
1 answer:
Answer:
12 M
Explanation:
The reaction between HNO₃ and KOH is:
First we <u>calculate how many KOH moles reacted with the diluted HNO₃ sample</u>, using<em> the given volume and concentration</em>:
- 50.0 mL * 0.60 M = 30 mmol KOH
As 1 KOH mol reacts with 1 HNO₃ mol, in 25 mL of the diluted HNO₃ solution there are 30 HNO₃ mmoles.
With that information in mind we can <u>calculate the HNO₃ concentration in the diluted solution</u>:
- 30 mmol HNO₃ / 25 mL = 1.2 M
Finally we can<em> use the C₁V₁=C₂V₂ formula</em> to <u>calculate the concentration of the original solution</u>:
- C₁ * 10.0 mL = 1.2 M * 100.00 mL
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Answer:
200 watts
Explanation:
First we have to find total work:
W =F(d)
W = 400J
Then plug that answer into the Power formula.
P = W/(t_f-t-i)
P = 400/2s
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