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Digiron [165]
3 years ago
8

Pls answer how many neutrons, protons, and electrons there are. I will give points, thanks, 5 stars, and brainliest if you answe

r correctly. Thank you and have a nice day :)

Chemistry
1 answer:
kirill115 [55]3 years ago
8 0

Answer:

19 electron 19 proton 20 neutrons

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Calculate the equilibrium constant for the following reaction: Co2+ (aq) + Zn(s> CO (s) + Zn2+ (aq)
Simora [160]

<u>Answer:</u> The K_{eq} of the reaction is 1.73\times 10^{16}

<u>Explanation:</u>

For the given half reactions:

Oxidation half reaction: Zn(s)\rightarrow Zn^{2+}+2e^-;E^o_{Zn^{2+}/Zn}=-0.76V

Reduction half reaction: Co^{2+}+2e^-\rightarrow Co(s);E^o_{Co^{2+}/Co}=-0.28V

Net reaction: Zn(s)+Co^{2+}\rightarrow Zn^{2+}+Co(s)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=-0.28-(-0.76)=0.48V

To calculate equilibrium constant, we use the relation between Gibbs free energy, which is:

\Delta G^o=-nfE^o_{cell}

and,

\Delta G^o=-RT\ln K_{eq}

Equating these two equations, we get:

nfE^o_{cell}=RT\ln K_{eq}

where,

n = number of electrons transferred = 2

F = Faraday's constant = 96500 C

E^o_{cell} = standard electrode potential of the cell = 0.48 V

R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = 25^oC=[273+25]=298K

K_{eq} = equilibrium constant of the reaction = ?

Putting values in above equation, we get:

2\times 96500\times 0.48=8.314\times 298\times \ln K_{eq}\\\\K_{eq}=1.73\times 10^{16}

Hence, the K_{eq} of the reaction is 1.73\times 10^{16}

8 0
3 years ago
Which statement is not true? *
Ronch [10]

bases have a ph lower than 7 is false. it's actually acids that have a ph lower than 7, 7 is neutral, and above 7 to 14 is basic.

7 0
4 years ago
Explain how two object create heat went rub quickly
sergiy2304 [10]

Answer:

friction

Explanation:

the resistance that one surface or object encounters when moving over another.

4 0
2 years ago
The minimum amount of 100-degree-c steam needed to melt 1 gram of 0-degree-celsius ice is
kvv77 [185]
The mass of ice to be melted is
1 g = 10⁻³ kg.

Let m =  the mass of steam required to melt the ice.

For water,
The latent heat of vaporization is 2260 kJ/kg
The latent heat of fusion is 334 kJ/kg

The steam should give up its latent heat of vaporization to melt the ice, which gives up its latent heat of fusion.
Therefore
(m kg)*(2260 kJ/kg) = (10⁻³ kg)*(334 kJ/kg)
m = 1.478 x 10⁻⁴ kg = 0.1478 g

Answer: 0.148 g

7 0
4 years ago
What is the pH for a solution that has an OH ion
Basile [38]
Assuming that you mean 10^-4 M then this would be basic and would have a pH of 10.

pOH = -log[OH].
So pOH = 4
pH=14-pOH
pH = 10
3 0
3 years ago
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