We are given
Jim's backyard:
Length is
![L=15\frac{5}{6} =\frac{95}{6} yards](https://tex.z-dn.net/?f=L%3D15%5Cfrac%7B5%7D%7B6%7D%20%3D%5Cfrac%7B95%7D%7B6%7D%20yards)
width is
![W=10\frac{2}{5} =\frac{52}{5} yards](https://tex.z-dn.net/?f=W%3D10%5Cfrac%7B2%7D%7B5%7D%20%3D%5Cfrac%7B52%7D%7B5%7D%20yards)
Since, this is rectangle
so, we can find area of rectangle
![A=L*W](https://tex.z-dn.net/?f=A%3DL%2AW)
![A=(\frac{95}{6})*(\frac{52}{5})](https://tex.z-dn.net/?f=A%3D%28%5Cfrac%7B95%7D%7B6%7D%29%2A%28%5Cfrac%7B52%7D%7B5%7D%29)
![A=\frac{494}{3} yard^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B494%7D%7B3%7D%20yard%5E2)
Area of one sod:
length is
![l=1\frac{1}{3} =\frac{4}{3} yards](https://tex.z-dn.net/?f=l%3D1%5Cfrac%7B1%7D%7B3%7D%20%3D%5Cfrac%7B4%7D%7B3%7D%20yards)
width is
![w=1\frac{1}{3} =\frac{4}{3} yards](https://tex.z-dn.net/?f=w%3D1%5Cfrac%7B1%7D%7B3%7D%20%3D%5Cfrac%7B4%7D%7B3%7D%20yards)
Since, it is rectangle in shape
so,
![Area=l*w](https://tex.z-dn.net/?f=Area%3Dl%2Aw)
![A=\frac{4}{3}*\frac{4}{3}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B4%7D%7B3%7D%2A%5Cfrac%7B4%7D%7B3%7D)
![A=\frac{16}{9}yard^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B16%7D%7B9%7Dyard%5E2)
Number of pieces of sod:
we can use formula
Number of pieces of sod = (area of Jim's backyard)/(area of one sod)
![N=\frac{\frac{494}{3} }{\frac{16}{9} }](https://tex.z-dn.net/?f=N%3D%5Cfrac%7B%5Cfrac%7B494%7D%7B3%7D%20%7D%7B%5Cfrac%7B16%7D%7B9%7D%20%7D)
now, we can simplify it
pieces need ..............Answer
Answer:
2 9/10
Step-by-step explanation:
subtract the 1 mile from the 3 9/10 mile. kinda like 3-1 but then you put the other stuff on the end (9/10)
I'm pretty sure this is the correct answer
2 7/8= 2/3L
Divide both sides by 2/3 and get 4.31 or 4 5/16
Y ^(-2/3)^-6 = y^12/3 = y^4
x^(1/2)^ -6 = x^-3 = 1 x^3
so the answer is y^4 * 1 /x^3 = y^4 / x^3
A