Answer:
16.86 ft/s
Step-by-step explanation:
Given that
Speed of the carousel, s = 14 rpm
Distance from the carousel, d = 23 ft
To start with, we convert the given speed to revolution per second, so that
s = 14/60 rev/sec
To find the needed speed, we use the formula
v =2πnR, remember that Diameter = 2R, so we substitute D for 2R and get πnD
v = πnD, and we use this to find our needed velocity
v = 3.142 * 14/60 * 23
v = 72.266 * 14/60
v = 16.86 ft/s
Therefore the boy must run at a speed of 16.86 ft/s in order to be able to match the carousel and jump on it
Answer:
15x*45 i think
Step-by-step explanation:
Solve for R:
R + 3 = -(1/2 + 6)
Put 1/2 + 6 over the common denominator 2. 1/2 + 6 = (2×6)/2 + 1/2:
R + 3 = -(2×6)/2 + 1/2
2×6 = 12:
R + 3 = -(12/2 + 1/2)
12/2 + 1/2 = (12 + 1)/2:
R + 3 = -(12 + 1)/2
12 + 1 = 13:
R + 3 = -13/2
Subtract 3 from both sides:
R + (3 - 3) = -13/2 - 3
3 - 3 = 0:
R = -13/2 - 3
Put -13/2 - 3 over the common denominator 2. -13/2 - 3 = (-13)/2 + (2 (-3))/2:
R = (-13)/2 - (3×2)/2
2 (-3) = -6:
R = (-6)/2 - 13/2
(-13)/2 - 6/2 = (-13 - 6)/2:
R = (-13 - 6)/2
-13 - 6 = -19:
Answer: R = (-19)/2
Answer:7 is I _9and 3
Step-by-step explanation:
Answer:
3*sqrt(3x)
--------------
2x
Step-by-step explanation:
To rationalize the denominator, we need to get rid of the square root. We need to multiply by sqrt(12x)/sqrt(12x)
9 sqrt(12x)
---------- * -----------
sqrt(12x) sqrt(12x)
9sqrt(12x)
-----------------
12x
We can cancel 3 in the top and bottom
3sqrt(12x)
---------------
4x
We also notice that 12 is made up of 4 and 3
3sqrt(4) sqrt(3x)
---------------
4x
3sqrt(4) sqrt(3x)
----------------------
4x
3*2sqrt(3x)
--------------
4x
We can cancel a 2 in the top and bottom
3*sqrt(3x)
--------------
2x
