A carbonate because the oxygen neutralizes the reactive coding of the calcium in its original form.
Answer:
-85 °C
Explanation:
O and S are in the same group( Group 16). Since S is below O it's atomic mass is higher than O. So molar mass of H2S is higher than H2O. The strength of Vanderwaal Interactions ( London dispersion forces) increases when the molar mass increases. However, only H2O can form H bonds with each other. This is because electronegativity of O is higher than S and therefore H in H2O has a higher partial positive charge than H of H2S.
H bond dominate among these 2 types of forces so the strength of attractions between molecules is higher in H2O than H2S. Therefore more energy should be supplied for H2O to break inter
molecular forces and convert from solid to liquid state than H2S. So mpt of H2O must be higher than that of H2S.
Answer:
THERE IS NOTHING MENTION HERE HOW CAN ANYONE KNOW ABOUT IT?]
Explanation:
The substance doesn't have a specific name. We just say that that substance is being reduced. Remember this mnemonic - OILRIG where "Oxidation is Loss, Reduction is Gain" of electrons.
Answer:
5.00 g calcium chloride in 95.0 g of water. Solute? ... (4 pts) Calculate the grams of copper (II) nitrate needed to make 100.0 mL of a 3.50 M solution
Explanation:
