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worty [1.4K]
3 years ago
13

Which component is missing from the process of cellular respiration? Glucose + Oxygen → Carbon Dioxide + ________ + Energy

Chemistry
2 answers:
damaskus [11]3 years ago
8 0

The answer is: Water.

Chemical reaction of cellular respiration (convert biochemical energy):

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O.  

glucose + oxygen → carbon dioxide + water + energy .  

This reaction is exothermic (energy is released).  

Carbon dioxide and water are released during cellular respiration.  

In cellular respiration where organic matter is transformed into carbon dioxide and energy is released for production of ATP.

Glucose and oxygen are reactants and carbon dioxide, water and energy are products of this chemical reaction; cellular respiration creates an energy molecule (ATP) when glucose is broken down.    

professor190 [17]3 years ago
4 0
<span>Glucose + Oxygen → Carbon Dioxide + ________ + Energy 

C6 H12 O6 +  O2     </span>→    CO2    +   H2O  + Energy 

The component that is missing is Water


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Answer: The osmotic pressure of a solution is 53.05 atm

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = ?

i = Van't hoff factor = 1 (for non-electrolytes)

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Volume of solution = 321 mL

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

\pi=1\times \frac{22.3\times 1000}{32.04\times 321}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K

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3 years ago
A 0.5 mol sample of He(g) and a 0.5 mol sample of Ne(g) are placed separately in two 10.0 L rigid containers at 25°C. Each conta
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rate of diffusion of He/rate of difussion of Ne=√4/10=√0.4=0.63

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