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Setler79 [48]
3 years ago
9

How many carbon monoxide molecules are in 0.75 moles of carbon monoxide

Chemistry
2 answers:
Naddika [18.5K]3 years ago
4 0

Hello!

Firstly, we need to determine the atomic formula of carbon monoxide.

When breaking down the name, we know that there is only one carbon atom since we normally do not add the prefix mono- (one), in the front of the first element. Secondly, there is one oxygen atom since mono = one, and oxide is oxygen. Carbon monoxide is written as: CO.

Now, to find the number of molecules, we will need to use a conversion factor, and also we must know Avogadro's number: <u>6.02 x 10^23 molecules</u>.

To set up the conversion factor, we must change the units from "moles CO" to "molecules CO". To do that, we will begin with the given number, "0.75 moles CO", and multiply that by "6.02 x 10^23 molecules CO over 1 mol CO".

0.75 moles CO x (6.02 x 10^23 molecules CO / 1 mol CO) = 4.52 x 10^23 molecules CO

Therefore, there are about 4.52 x 10^23 molecules CO.

masya89 [10]3 years ago
3 0
0.75 x 6.02x 10^23
No of molecules = no of moles x avogadro’s number
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3 years ago
Given that the molar mass of NaCl is 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of NaCl in 500. mL of
melomori [17]
Hi friend,

the \: answer \: is \: 3 \: molar
the solution is as follows

moles  \: of  \: NaCl \:  in  \: the \:  solution

=
give \: mass \: of \: sodium \: chloride \\  -  -  -  -  -  -  -  -  -  -  -   -  -  -  -  -  \\ molecular \: mass \: of \: sodium \: chloride \:

=
\:  \:  87.75 \\  -  -  -   -  \\  \:  \: 58.44
=  \: 1.501 \: moles

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: moles \: of \: solute \\ Molarity \:  =      \:  \:  \:  \:  \: -  -  -  -  -  -  -     \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \: volume \: of \: solution(litrs)
applying \: the \: formulae \:
converting ml to litres

1.501/(500/1000)

1.501 X 2

3 M



Hope it helps


4 0
3 years ago
Read 2 more answers
A sample of hydrogen (H2) gas is collected over water at 35oC and 725 mm. The volume of the gas collected is 72.0 ml. How many m
WARRIOR [948]

Answer:

2.56 × 10⁻³ mol

5.17 × 10⁻³ g

Explanation:

Given data

Temperature = 35°C + 273 = 308 K

Pressure = 725 mmHg

Volume = 72.0 mL = 0.0720 L

The vapor pressure of water at 35°C is 42.20 mmHg. The total pressure is equal to the sum of the partial pressures.

P = pH₂ + pH₂O

pH₂ = P - pH₂O = 725 mmHg - 42.20 mmHg = 683 mmHg

pH₂ = 683 mmHg × (1 atm / 760 mmHg) = 0.899 atm

We can find the moles of H₂ using the ideal gas equation.

P × V = n × R × T

0.899 atm × 0.0720 L = n × (0.08206 atm.L/mol.K) × 308 K

n = 2.56 × 10⁻³ mol

The molar mass of H₂ is 2.02 g/mol. The mass of H₂ is:

2.56 × 10⁻³ mol × 2.02 g/mol = 5.17 × 10⁻³ g

3 0
3 years ago
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