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Jet001 [13]
3 years ago
13

You have a square that has a side length of $1$ centimeter. Each minute, $2$ centimeters are added to the side length. After $10

$ minutes, what will be the difference between the area of the last square and the area of the initial square in square centimeters (do not include the units in your answer)?
Mathematics
1 answer:
Mariulka [41]3 years ago
5 0

Answer:

Difference in area of the last square and the initial square = 440 cm²

Step-by-step explanation:

Length of the side of a square = 1 cm

Area of the square = (side)² = 1 cm²

Addition of side length every minute = 2 cm

After x minutes length of each side of the square = (1 + 2x) cm

If x = 10 minutes

Length of each side of the square = [1 + 2(10)]

                                                         = 21 cm

Area of the square after 10 minutes = (21)²

                                                            = 441 cm²

Therefore, difference in area of the last square and area of the initial square

= 441 - 1

= 440 cm²

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Step-by-step explanation:

Hi there!

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5 0
3 years ago
The population of the town is 2500 and is decreasing at a rate of 3% per year. determine the population after 11 years
Debora [2.8K]

Answer:

\huge \boxed{ \boxed{1675}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • percent
  • percentage words problem
  • PEMDAS
<h3>given:</h3>
  • population:2500
  • decreasing rate:3%
<h3>to find:</h3>
  • the population after 11 years
<h3>let's solve:</h3>

according to the question

population decreases in 1 year

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population will decrease in 11 years

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  • 825

so the population of the town after 11 years will be

2500-825

<h2>1675</h2>
4 0
3 years ago
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