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Mariana [72]
3 years ago
5

2. Combine lead (II) nitrate and potassium iodide solutions.

Chemistry
1 answer:
olga_2 [115]3 years ago
6 0

Answer:

Pb(NO3)2+ 2Kl →PbI2 + 2KNO3

Mg + 2HCl → MgCl2 + H2

4H2O → 4H^+ + 4OH^-

2Mg + O2 → 2MgO

Explanation:

This question has to do with the balancing of chemical reaction equations. The general rule for balancing chemical reaction equation is that the number of atoms of each element on the left hand side of the reaction equation must be equal to the number of atoms of the same element on the right hand side of the reaction equation.

This principle was followed in balancing each reaction equation above. For instance, in the burning of magnesium, there are two atoms of both magnesium and oxygen on either side of the reaction equation.

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Dissolved hydrofluoric acid reacts with dissolved sodium hydroxide to form water and aqueous sodium fluoride
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Answer:

HF(aq)+NaOH(aq)→NaF(aq)+H2O(l)

Explanation:

Complete question

Dissolved hydrofluoric acid reacts with dissolved sodium hydroxide to form water and aqueous sodium fluoride. What is the net ionic equation

Equilibrium equation between the undissociated acid and the dissociated ions

HF(aq)⇌H+(aq)+F−(aq)

Sodium hydroxide will dissociate aqueous solution to produce sodium cations, Na+, and hydroxide anions, OH−

NaOH(aq)→Na+(aq)+OH−(aq)

Hydroxide anions and the hydrogen cations will neutralize each other to produce water.

H+(aq)+OH−(aq)→H2O(l)

On combining both the equation, we get –  

HF(aq)+Na+(aq)+OH−(aq)→Na+(aq)+F−(aq)+H2O(l)

The Final equation is  

HF(aq)+NaOH(aq)→NaF(aq)+H2O(l)

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