Accuracy is more of a range
Answer:
: conjugate acid of 
: conjugate base of 
: conjugate base of 
: conjugate acid of 
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

Here in forward reaction
is accepting a proton, thus it is considered as a base and after accepting a proton, it forms
which is a conjugate acid.
And
is losing a proton, thus it is considered as an acid and after loosing a proton, it forms
which is a conjugate base.
Similarly in the backward reaction,
is loosing a proton, thus it is considered as a acid and after loosing a proton, it forms
which is a conjugate base.
And
is accepting a proton, thus it is considered as a base and after accepting a proton, it forms
which is a conjugate acid.
Here we have to get the product between the reaction of butane-1-amine with methyl iodide (CH₃I).
The reaction between 1 mole of butan-1-amine and 1 mole of methyl iodide produces Methyl-butamine which is a secondary amine.
However, In presence of 2 moles of methyl iodide the reaction proceed to N, N-di-methylbutamine. The reaction is shown in the figure.
This is one of the effective reaction method to generate secondary and tertiary amine from primary amine.
The primary amine reacts with alkyl iodide to form secondary to tertiary amine. The final product depends upon the quantity of the alkyl iodide present in the reaction.
<span>When the gases dihydrogen sulfide and oxygen react, they form the gases sulfur dioxide and water vapor. so the balanced equation is
</span>2H2S(g) + 3O2(g) → 2SO2(g) + 2H2O(l)
hope it helps