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Tema [17]
3 years ago
7

What is the name for point along an axon where an impulse jumps

Physics
1 answer:
Mrrafil [7]3 years ago
6 0
The answer is Nodes of Ranvier. Hope this helps.

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A gymnast of mass 62.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t
MrRissso [65]

Answer:

a) T = 608.22 N

b) T = 608.22 N

c) T = 682.62 N

d) T = 533.82 N

Explanation:

Given that the mass of gymnast is m = 62.0 kg

Acceleration due to gravity is g = 9.81 m/s²

Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.

So;

To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;

T = mg

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs the rope at a constant rate tension in the string is

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs up the rope with an upward acceleration of magnitude

a = 1.2 m/s²

the tension in the string is  T - mg = ma (Since acceleration a is upwards)

T = ma + mg

= m (a + g )

= (62.0 kg)(9.81 m/s² + 1.2  m/s²)

= (62.0 kg) (11.01 m/s²)

= 682.62 N

When the gymnast climbs up the rope with an downward acceleration of magnitude

a = 1.2 m/s² the tension in the string is  mg - T = ma (Since acceleration a is downwards)

T = mg - ma

= m (g - a )

= (62.0 kg)(9.81 m/s² - 1.2 m/s²)

= (62.0 kg)(8.61 m/s²)

= 533.82 N

5 0
2 years ago
Est ce qu’un cricket c’est un consommateur
Sholpan [36]

Answer:

Oui

Explanation:

7 0
3 years ago
What do radio waves and microwaves have in common?
MAVERICK [17]
#3, they both come after infared and are not harmful to living cells.
6 0
3 years ago
How does a toaster oven use micro waves
vekshin1
It uses microwaves as little heatwaves and uses them to heat the food
5 0
3 years ago
A speeding motorist traveling with velocity Vm is spotted by a police car. The police car is initially at rest, but the instant
Svetlanka [38]

Answer:

Explanation:

Given

Let us suppose police car and motorist travel in straight line  and police car catches motorist after s distance

Distance travel by motorist

s=v_mt----1

Distance traveled by Police car

s=ut+\frac{at^2}{2}

s=0+\frac{a_pt^2}{2}

s=\frac{a_pt^2}{2}----2

from 1 & 2 we get

t=\frac{2v_m}{a_p}

(a)Velocity of Police car after t sec

v=u+a_pt

v=0+a_p\times \frac{2v_m}{a_p}

v=2v_m

(b)time taken by police car is

t=\frac{2v_m}{a_p}

(c)Distance travel by police car=\frac{2v_m^2}{a_p}

7 0
2 years ago
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