Given
P(1,-3); P'(-3,1)
Q(3,-2);Q'(-2,3)
R(3,-3);R'(-3,3)
S(2,-4);S'(-4,2)
By observing the relationship between P and P', Q and Q',.... we note that
(x,y)->(y,x) which corresponds to a single reflection about the line y=x.
Alternatively, the same result may be obtained by first reflecting about the x-axis, then a positive (clockwise) rotation of 90 degrees, as follows:
Sx(x,y)->(x,-y) [ reflection about x-axis ]
R90(x,y)->(-y,x) [ positive rotation of 90 degrees ]
combined or composite transformation
R90. Sx (x,y)-> R90(x,-y) -> (y,x)
Similarly similar composite transformation may be obtained by a reflection about the y-axis, followed by a rotation of -90 (or 270) degrees, as follows:
Sy(x,y)->(-x,y)
R270(x,y)->(y,-x)
=>
R270.Sy(x,y)->R270(-x,y)->(y,x)
So in summary, three ways have been presented to make the required transformation, two of which are composite transformations (sequence).
About 6 times. 6.4 to be exact!
Hello,
Let's assume f the age of the father,
s the age of the son.
<span>The age of a father is 2 less than 7 times the age of his son ==> f=7s-2 (1)
</span>
<span>In 3 years, the sum of their ages will be 52 ==>(f+3)+(s+3)=52 (2)
(2)==>f+s+6=52
==>f+s=46 (3)
(3) and (1) ==>7s-2+s=46
==>8s=48
==>s=6
f=46-6=40
</span>
The other two linear factors of the polynomial x³ + 4x² +x -6 are; Choice A: (x – 1) and (x + 3)
<h3>Polynomial division</h3>
By ling division of polynomials, it follows that the division of polynomial x³ + 4x² +x -6 by x +2 yields the quadratic expression;
On this note, the factorisation of the quadratic expression above yields factors;
Read more on factorisation of polynomials;
brainly.com/question/280849
Answer:
Step-by-step explanation:
Number of electronic systems = 6
(a) Number of defected systems = 2
Probability of getting at least one system is defective
1 defective and 1 non defective + 2 defective
= (2 C 1 ) x (4 C 1) + (2 C 2) / (6 C 2)
= 3 / 5
(b) four defective
Probability of getting at least one system is defective
2 defective and 2 non defective + 3 defective and 1 non defective + 4 defective
= (4 C 2 ) x (2 C 2) + (4 C 3 )(2 C 1) + (4 C 4) / (6 C 4)
= 1
