Answer: a. 17.7 KJ/Mol
b. T=210K
Explanation:
Arsine, ash3 is a highly toxic compound used in the electronics industry for the production of semiconductors. its vapor pressure is 35 torr at – 111.95°c and 253 torr at – 83.6°c. using these data calculate.
the question isnt completely originally, but we could look at the likely derivation from the questions
(a) the standard enthalpy of vaporization
using the clausius clapeyron equation
In (PT1vap / PT2vap) = delta H (vap) / R ( (1/T1) - (1/T2) )
In (35Torr/253Torr) = delta H (vap) / 8.3145 ( (1/189.55) - (1/161.2) )
Therefore, Delta H (vap) = 17.7 KJ/Mol
b. Also the boiling point
What is the normal boiling point of arsine?
At the boiling point Pvap = atmospheric pressure = 1 atm=760 torr
substitution into the equation as stated in question 1
ln(760/253)=17700/8.314(1/189.55-1/T)
T=210K
Explanation:
The nearest star to the Earth is the red dwarf star Proxima Centauri, at a distance of 4.218 light-years.
Light year is the unit of distance covered by the heavenly bodies. 1 light year is equal to :
So,
We need to convert 4.218 light-years barley corns.
Since, 1 barleycorn = 1/3 inch


So, the nearest star to the Earth is at a distance of
. Hence, this is the required solution.
Answer:
Explanation:
The x component is the adjacent side making up the given angle (39.4)
The vector is the hypotenuse.
The definition of the cos (x) is adjacent / hypotenuse.
cos(39.4) = adjacent / 47.3 Multiply both sides by 47.3
47.3 * cos(39.4) = adjacent Cos(39.4) = 0.7727
adjacent = 36.55
Answer: 
Explanation:
Given
mass of laptop m=2 kg
The velocity of car u=8 m/s
The coefficient of static friction is 
The coefficient of kinetic friction is 
As the car is moving, so the coefficient of kinetic friction comes into play
deceleration offered by friction 
Using the equation of motion 
insert the values

Answer:
the period of the 16 m pendulum is twice the period of the 4 m pendulum
Explanation:
Recall that the period (T) of a pendulum of length (L) is defined as:

where "g" is the local acceleration of gravity.
SInce both pendulums are at the same place, "g" is the same for both, and when we compare the two periods, we get:

therefore the period of the 16 m pendulum is twice the period of the 4 m pendulum.