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ss7ja [257]
3 years ago
13

The earth exerts a gravitational force of 500 N on Amy. What is Amy’s mass in kg?

Physics
1 answer:
White raven [17]3 years ago
6 0

Gravitational force of earth is given as weight of object

so here we know that gravitational force on Amy is 500 N

so we will have

mg = 500 N

now we will have

g = 9.8 m/s^2

now from above equation we will have

m (9.8 m/s^2) = 500 N

m = \frac{500}{9.8} kg

m = 51 kg

so the mass of the Amy is 51 kg

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A uniform stick 1.5 m long with a total mass of 250 g is pivoted at its center. A 3.3-g bullet is shot through the stick midway
Andru [333]

Answer:

<em>63.44 rad/s</em>

<em></em>

Explanation:

mass of bullet = 3.3 g = 0.0033 kg

initial velocity of bullet v_{1} = 250 m/s

final velocity of bullet v_{2} = 140 m/s

loss of kinetic energy of the bullet = \frac{1}{2}m(v^{2} _{1} - v^{2} _{2})

==> \frac{1}{2}*0.0033*(250^{2}  - 140^{2} ) = 70.785 J

this energy is given to the stick

The stick has mass = 250 g =0.25 kg

its kinetic energy = 70.785 J

from

KE = \frac{1}{2} mv^{2}

70.785 = \frac{1}{2}*0.25*v^{2}

566.28 = v^{2}

v= \sqrt{566.28} = 23.79 m/s

the stick is 1.5 m long

this energy is impacted midway between the pivot and one end of the stick, which leaves it with a radius of 1.5/4 = 0.375 m

The angular speed will be

Ω = v/r = 23.79/0.375 =<em> 63.44 rad/s</em>

5 0
3 years ago
What is the displacement of an object during a specific unit of time.
strojnjashka [21]

Answer:

velocity

Explanation:

the displacement of an object during a specific unit of time.

7 0
3 years ago
when forces on an object are acting in the same direction, how do you add them together to find the net force?
AysviL [449]
If two forces act on an object in the same direction, the net force is equal to the sum of the two forces
4 0
3 years ago
A group of skydiver are riding in a helicopter up to the spot form which they will jump. As they ride upwards. their gravitation
Dafna1 [17]

A group of skydiver are riding in a helicopter up to the spot form which they will jump. As they ride upwards. their gravitational potential energy increases.

Answer: Option A

<u>Explanation:</u>

Gravitational potential energy refers exerted energy on any object rising from the surface of Earth. It is the measurement of potential energy of any object depending on its position.

We can also define gravitational potential energy as the amount of energy required to raise an object to certain level from the surface of Earth or the work done to raise the object to some position from a position of reference. The formula for calculating the gravitational potential energy is

               \text {Gravitational potential energy}=m g \Delta h

Here, m is the object's mass, g -the acceleration and \Delta h - the object's distance from the Earth's surface.

So from this formula, it can be confirmed that if the helicopter carrying skydivers are made to ride upwards, then their gravitational potential energy will increase as the distance of helicopter from the Earth's surface is increased on riding the helicopter upwards.

6 0
3 years ago
A red laser from the physics lab is marked as producing 632.8-nm light. When light from this laser falls on two closely spaced s
BARSIC [14]

Answer:

The wavelength is  \lambda_R  =  649 *10^{-9}\ m

Explanation:

From the question we are told that

   The wavelength of the red laser is  \lambda_r  =  632.8 \ nm =  632.8 *10^{-9}\ m

    The spacing between  the fringe is  y_r  =  6.00\ mm =  6.00*10^{-3}  \  m

   The spacing between  the fringe for smaller laser point  is  y_R   = 6.19 \ mm =  6.19 *10^{-3} \  m

      Generally the spacing between  the fringe is mathematically represented as

       y  =  \frac{D *  \lambda  }{d}

Here  D is the distance to the screen

    and  d is the distance of the slit separation

Now for both laser red light light and  small laser  point  D and  d are same for this experiment

So

         \frac{y_r}{\lambda_r}  =  \frac{D}{d}

=>      \frac{y_r}{\lambda_r}  = \frac{y_R}{\lambda_R}

Where \lambda_R  is the wavelength produced by the small laser pointer

  So

           \frac{6.0 *10^{-3}}{ 632.8*10^{-9}}  = \frac{ 6.15 *10^{-9}}{\lambda_R}

=>       \lambda_R  =  649 *10^{-9}\ m

7 0
3 years ago
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