Question

A circuit in a radio receiver requires a current of at least 1.0 microamp in order to detect a signal. How many electrons pass through the circuit if it detects a signal which persists for 1.0 microsecond

Answer 1

Answer:

The number of electrons passes through the circuit if it detects a signal which persists for 1.0 microseconds is $6.25\times 10^{6}$.

Explanation:

A circuit in a radio receiver requires a current of at least 1.0 microamp in order to detect a signal. It is required to find the number of electrons passing through the circuit if it detects a signal which persists for 1.0 microseconds.

It is known that the total amount of charge passing through a circuit is calculated as, Q=It.

Where I is the amount of current passing through a time of t.

For this problem, I=1.0 microamp, and t=1.0 microseconds. Therefore the amount of charge is,

$\begin{aligned}Q&=I\times t\\&=1.0\text{ }\mu\text{A}\times 1.0\text{ }\mu\text{s}\\&=1.0\times 10^{-6}\text{ }\mu\text{A}\times 1.0\times 10^{-6}\text{ }\mu\text{s}\\&=10^{-12} \text{ C}\end{aligned}$

The amount of charge in one electron is $e=1.6\times 10^{-19} \times{ C}$, therefore the number of electrons passing through the circuit while carrying $10^{-12} \text{ C}$ amount of charge is,

$\begin{aligned}n&=\frac{Q}{e}\\&=\frac{10^{-12} \text{ C}}{1.6\times 10^{-19} \times{ C}}\\&=6.25\times 10^{6}\end{aligned}$

To know more about the number of electrons passing through the circuit, refer to:

brainly.com/question/13199730

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