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3 years ago

A clear, pure liquid sample is brought into the lab and exposed to an electrical current. Different gases are

Chemistry

2 answers:

mel-nik [20]3 years ago

4 0

I think it’s a d but I’m not sure

Tresset [83]3 years ago

4 0

I think the answer is an element

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Which of the following explains how electricity flows? Protons flow from the positive end of a source towards the negative end.E

zalisa [80]

I know for a fact the answer would (not) be the last option. This would not be a way that electricity would be able to really flow.

Your correct answer would be of when the "e<span>lectrons flow from the negative end of a source towards the positive end."

This would be because when the electrons would be free, they would have enough energy to then move from the negative side of the end, to the positive side.</span>

7 0

3 years ago

Calculate the molecular mass of a 2.66g sample of gas at a temperature of pressure of 845torr and occupying a volume of 0.70L.

ratelena [41]

The molecular mass of a 2.66g sample of gas at a temperature of pressure of 845torr and occupying a volume of 0.70L is 84.16g/mol.

<h3>How to calculate molecular mass?</h3>

The molecular mass can be calculated by first calculating the number of moles using the following formula:

PV = nRT

Where;

P = pressure
V = volume
n = no of moles
R = gas law constant
T = temperature

1.112 × 0.7 = n × 0.0821 × 300

0.7784 = 24.63n

n = 0.032mol

molecular mass = 2.66g ÷ 0.032mol

molecular mass = 84.16g/mol

Therefore, the molecular mass of a 2.66g sample of gas at a temperature of pressure of 845torr and occupying a volume of 0.70L is 84.16g/mol.

Learn more about molar mass at: brainly.com/question/14122402

#SPJ1

8 0

2 years ago

What normally determines whether a substance is a liquid, solid, gas, or plasma?

mrs_skeptik [129]

The motion or kinetic energy of the particles determine the state of matter

4 0

3 years ago

A gas has an initial volume of 52.3 L at 273 Kelvin. What is its temperature when the volume reaches 145.7 L?

erastovalidia [21]

Answer:

$\boxed {\boxed {\sf 761 \ K}}$

Explanation:

We are asked to find the new temperature of a gas after a change in volume. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula for this law is:

$\frac {V_1}{T_1}= \frac{V_2}{T_2}$

The volume is initially 52.3 liters at a temperature of 273 Kelvin.

$\frac {52.3 \ L}{273 \ K}= \frac{V_2}{T_2}$

The volume reaches 145.7 liters at an unknown temperature.

$\frac {52.3 \ L}{273 \ K}= \frac{145.7 \ L }{T_2}$

We are solving for the new temperature, so we must isolate the variable T₂. Cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.

$52.3 \ L * T_2 = 273 \ K * 145.7 \ L$

Now the variable is being multiplied by 52.3 liters. The inverse of multiplication is division. Divide both sides by 52.3 L.

$\frac {52.3 \ L * T_2 }{52.3 \ L}=\frac{ 273 \ K * 145.7 \ L}{52.3 \ L}$

$T_2=\frac{ 273 \ K * 145.7 \ L}{52.3 \ L}$

The units of liters cancel.

$T_2=\frac{ 273 \ K * 145.7 }{52.3 }$

$T_2 = 760.5372849 \ K$

The original measurements have at least 3 significant figures, so our answer must have 3. For the number we found, that is the ones place. The 5 in the tenths place tells us to round the 0 up to a 1.

$T_2 \approx 761 \ K$

When the volume reaches 145.7 liters, the temperature is <u>761 Kelvin.</u>

8 0

3 years ago

Calculate the ph of a mixture that contains 0.18 m of hno3 and 0.24 m of hbro

Kobotan [32]

HNO3 is a strong acid while HBrO is weak acid.
Therefore we ignore the presence of the weak acid such that we consider the pH of the strong acid.
Therefore; since pH= - log (H+)
Hence pH= -log 0.18
= 0.745
Thus the pH of the mixture is 0.745

7 0

4 years ago