What are 3 ways living creatures use carbohydrates

2 answers:

8 0

Plants polymerise carbs to synthesise cellulose as a structural molecule

Animals synthesise glycogen to circulate a rapidly accessible molecule for chemical energy

Carbohydrate molecules added to proteins in membranes can be used to cell-cell adhesion.

Depending on what level of chemistry you are studying. A simpler answer is they are used
As a fuel of energy
Anti coagulant
And to store food

Degger [83]4 years ago

5 0

<span>Quick Energy, Energy Storage, and Structure.</span>

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For each of the following compounds, write the symbols of the ions in the compound, and the number of each ion in the molecule o

Kay [80]

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3 years ago

Why did the laser beam move when the magnet was placed near it

podryga [215]

No because the light can only produce the color the manufacturer gave it and it is thin air unless the laser beam was able to make things on fire then the substance would be called a gas

4 0

3 years ago

uman blood is kept at a typical pH of 7.40 mainly by the carbonic acid–carbonate ion buffer system. The corresponding chemical e

nadya68 [22]

Answer:

The ratio, $\frac{[HCO_{3}^{-}]}{[H_{2}CO_{3}]}$ , is 10.7

Explanation:

$H_{2}CO_{3}$ is an weak acid and $HCO_{3}^{-}$ is it's conjugate base.

So, according to Henderson-Hasselbalch equation, pH of this buffer system can be represented as-

$pH=pK_{a}(H_{2}CO_{3})+log(\frac{[HCO_{3}^{-}]}{[H_{2}CO_{3}]})$

Here pH=7.40, $pK_{a}(H_{2}CO_{3})$ =6.37

So, $7.40=6.37+log(\frac{[HCO_{3}^{-}]}{[H_{2}CO_{3}]})$

or, $\frac{[HCO_{3}^{-}]}{[H_{2}CO_{3}]}=10.7$

So the ratio, $\frac{[HCO_{3}^{-}]}{[H_{2}CO_{3}]}$ , is 10.7

6 0

4 years ago

Ammonia (NH3) ionizes according to the following reaction: NH3(aq) + H2O(l) ⇌ NH4+(aq) + OH–(aq) The base dissociation constant

Ira Lisetskai [31]

Answer:

pH = 9.6

Explanation:

According to Brönsted-Lowry theory, NH₃ is a base and NH₄⁺ its conjugate acid. When they are together in a solution, the form a buffer, which is used to resist abrupt changes in pH when an acid or a base is added. pOH fro a buffer can be found using Henderson-Hasselbalch equation.

$pOH = pKb + log\frac{conjugateacid}{base}$