With steps pls

Which equation is set up correctly to determine the volume of a 1.5 mole sample of oxygen gas at 22°C and 100 kPa?

LenKa [72]

The volume could be calculated by using V = n RT / P 

In which V = Volume
n = number of Moles
R= The Gas constant
T = Temperature (ideally this would be in Kelvin, but i don't see it in the option)
P = Pressure

I believe the answer is

V = (1.5mol) (0.08205 L*kPa/K*mol) (22Celsius)/100 kPa

6 0

3 years ago

Consider the five balanced chemical reactions listed below, all using O2 as a reactant. Normally, O2 is an excess reagent for re

ad-work [718]

Answer: option E. None because in all the reactions O2 is in excess

Explanation:

7 0

2 years ago

A chemist must prepare 300.0mL of nitric acid solution with a pH of 0.70 at 25°C. He will do this in three steps: Fill a 300.0mL

d1i1m1o1n [39]

Answer: The volume of concentrated solution required is 9.95 mL

Explanation:

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

pH = 0.70

Putting values in above equation, we get:

$0.70=-\log[H^+]$

$[H^+]=10^{-0.70}=0.199M$

1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions.

Molarity of nitric acid = 0.199 M

To calculate the volume of the concentrated solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated nitric acid solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted nitric acid solution

We are given:

$M_1=7.0M\\V_1=?mL\\M_2=0.199M\\V_2=350mL$

Putting values in above equation, we get:

$7.0\times V_1=0.199\times 350.0\\\\V_1=\frac{0.199\times 350}{7.0}=9.95mL$

Hence, the volume of concentrated solution required is 9.95 mL

6 0

2 years ago

When water decomposes into oxygen and hydrogen, the mass

Maurinko [17]

When water decomposes into oxygen and hydrogen, the mass "Remains Constant" as according to Law of Conservation of mass, mass can neither be created not destroyed,.

In short, Your Answer would be Option A

Hope this helps!

8 0

3 years ago

1. A solution with a pH of 9 has a pOH of

Alecsey [184]

Answer:

strength = 10⁻²/10⁻³ = 10 times more acidic

Explanation:

1. A solution with a pH of 9 has a pOH of

pH + pOH = 14 => pOH = 14 - pH = 14 - 9 = 5

2. Which is more acidic, a solution with a pH of 6 or a pH of 4?

pH of 4 => Higher [H⁺] = 10⁻⁴M vs pH of 6 => [H⁺] = 10⁻⁶M

3. How many times more acidic is a solution with a pH of 2 than a solution with a pH of 3?

soln with pH = 2 => [H⁺] = 10⁻²M

soln with pH = 3 => [H⁺] = 10⁻³M

strength = 10⁻²/10⁻³ = 10 times more acidic

4. What is the hydrogen ion concentration [H + ] in a solution that has a pH of 8?

[H⁺] = 10^-pH = 10⁻⁸M

5. A solution has a pOH of 9.6. What is the pH? (Use the formula.)

pH + pOH = 14 => pH = 14 - 9.6 = 4.4

8 0

3 years ago