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Nikitich [7]
3 years ago
5

Hey any one ride dirtbikes here

Engineering
2 answers:
AveGali [126]3 years ago
4 0
Yeah why I have to give 20 words though so I'm talk a bunch please give brainly some troll keeps taking my points and giving fake answers
Serga [27]3 years ago
3 0

Answer:

Yes all the time

Explanation:

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The Micro:bit is considered a what?
Scrat [10]

Sorry need points I'm new

3 0
3 years ago
The proposed grading at a project site will consist of 25,100 m3 of cut and 23,300 m3 of fill and will be a balanced earthwork j
Anna [14]

Answer:

the volume of water that will be required to bring these soils to the optimum moisture content is 1859 kL

Explanation:

Given that;

volume of cut = 25,100 m³

Volume of dry soil fill = 23,300 m³

Weight of the soil will be;

⇒ 93% × 18.3 kN/m³ × 23,300 m³

= 0.93 × 426390 kN 3

= 396,542.7 kN  

Optimum moisture content = 12.9 %

Required amount of moisture = (12.9 - 8.3)% = 4.6 %

So,

Weight of water required = 4.6% × 396,542.7 = 18241 kN

Volume of water required = 18241 / 9.81 = 1859 m³

Volume of water required = 1859 kL

Therefore, the volume of water that will be required to bring these soils to the optimum moisture content is 1859 kL

6 0
3 years ago
If you had a match and a lantern and a candle in the dark which one would you choose to light.
PSYCHO15rus [73]

Answer:

The match

Explanation:

You can light both the lantern and the candle if you light the match first.

I don't know of this is a homework question, but I answered it anyway :)

5 0
3 years ago
Read 2 more answers
What kind of car is this
juin [17]

Answer:

camaro

Explanation:

5 0
3 years ago
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How high a building could fire hoses effectively spray from the ground? Fire hose pressures are around 1 MPa. (It is also said t
Mrac [35]

Answer:

z_{2} = 91.640\,m

Explanation:

The phenomenon can be modelled after the Bernoulli's Principle, in which the sum of heads related to pressure and kinetic energy on ground level is equal to the head related to gravity.

\frac{P_{1}}{\rho\cdot g} + \frac{v_{1}^{2}}{2\cdot g}= z_{2}+\frac{P_{2}}{\rho\cdot g}

The velocity of water delivered by the fire hose is:

v_{1} = \frac{(300\,\frac{gal}{min} )\cdot(\frac{3.785\times 10^{-3}\,m^{3}}{1\,gal} )\cdot(\frac{1\,min}{60\,s} )}{\frac{\pi}{4}\cdot (0.3\,m)^{2}}

v_{1} = 0.267\,\frac{m}{s}

The maximum height is cleared in the Bernoulli's equation:

z_{2}= \frac{P_{1}-P_{2}}{\rho\cdot g} + \frac{v_{1}^{2}}{2\cdot g}

z_{2}= \frac{1\times 10^{6}\,Pa-101.325\times 10^{3}\,Pa}{(1000\,\frac{kg}{m^{3}} )\cdot(9.807\,\frac{m}{s^{2}} )} + \frac{(0.267\,\frac{m}{s} )^{2}}{2\cdot (9.807\,\frac{m}{s^{2}} )}

z_{2} = 91.640\,m

7 0
3 years ago
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