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Nikitich [7]
3 years ago
5

Hey any one ride dirtbikes here

Engineering
2 answers:
AveGali [126]3 years ago
4 0
Yeah why I have to give 20 words though so I'm talk a bunch please give brainly some troll keeps taking my points and giving fake answers
Serga [27]3 years ago
3 0

Answer:

Yes all the time

Explanation:

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Write a script (Program 2) to perform t he following matrix operations. Use output commands to clearly output each problem with
Simora [160]

Find the attachments for complete solution

7 0
3 years ago
Which of the following positions would be responsible for attaching I-beams to a crane?
prohojiy [21]

Answer:

Rigger

Explanation:

<em> work as one</em>

4 0
3 years ago
How many gallons of 25% concentrated due will Lucy need to add to the 15% concentrated dye to make a batch with a concentration
Volgvan

Complete question is;

Lucy works for a company that manufactures liquid dyes for fabric. She currently wants to mix up some 23%-concentrated teal dye. She has 16 gallons of 15%-concentrated teal dye, as well as plenty of 25%-concentrated teal dye. How many gallons of the 25%-concentrated teal dye will Lucy need to add to the 15%-concentrated teal dye to make a batch with a concentration of 23%?

Answer:

64 gallons

Explanation:

We are given;

Quantity of 15%-concentrated teal dye = 16 gallons

Let the number of gallons of 25%-concentrated teal dye needed to add to make the batch with a concentration of 23% be represented as x.

Thus;

(15% × 16) + (25%)x = 23%(16 + x)

Multiply each term by 100 to give;

(15 × 16) + 25x = 23(16 + x)

240 + 25x = 368 + 23x

Rearranging, we have;

25x - 23x = 368 - 240

2x = 128

x = 128/2

x = 64

8 0
3 years ago
At what distance from the Earth’s surface is a 10,000 kg satellite if its potential energy is equal to –5.58 x 1011 J? (choose t
Maksim231197 [3]

Answer:

Option D

Explanation:

As we know

Gravitational Constant (G) = 6.67*10^{11}

Mass of Earth (M) = 5.98*10^{24}

Weight of satellite (m) = 10,000 Kg

Radius of Earth (R) = 6.378*10^6

Distance of satellite from Earth = \frac{GMm}{R} - U

Substituting the given values, we get

D=\frac{(-((6.67*10^{11})(5.98*10^{24})(10000))}{(6.378*10^6)} - (-5.58*10^{11})\\\\0.625*10^{3}Km

or 635 m

The correct answer is option D

3 0
3 years ago
Chemical engineering got is unofficial start around the time of the __________ __________ ________.
Yuri [45]
World war II i think
6 0
4 years ago
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