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IrinaK [193]
3 years ago
13

What is a physical property of snowflakes?

Physics
2 answers:
Otrada [13]3 years ago
5 0
A gas Bc snow is a vapor that freezes
zysi [14]3 years ago
4 0
The shape of the snowflake is determined broadly by the temperature and humidity at which it is formed. Rarely, at a temperature of around −2 °C (28 °F), snowflakes can form in threefold symmetry — triangular snowflakes. Most snow particles are irregular in form, despite their common depiction as symmetrical.
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Name the distance that is 10 times smaller than centimeter
Svetllana [295]
1 millimeter.

1 centimeter is 1/100th of a meter (1 cent of a meter). 
1 millimeter is 1/1000th of a meter.
6 0
3 years ago
Look at the circuit below. What is the voltage between points A and B?​
velikii [3]

Answer: B 2V

Explanation:

Since the voltage of the battery is 2V.

At point A and B, there is no voltage drop. So the voltage will still be same as in the battery which is 2V.

6 0
4 years ago
Read 2 more answers
How might temperature near ocean compare with those in land in winter ? In summer
omeli [17]
Well when your by the ocean your near more water. Snow is made of water. When you are next to a larger body of water you are most likely going to get more snow then if not living by a larger body of water. 

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8 0
4 years ago
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Calculate the exerted on the heel of a boy's foot if the boy weighs 320N and he lands on one heel which has an area of 0.15m squ
fenix001 [56]

Mujhe nhi pata sorry. Lekin mai bhut logo ko jaanti hoon jo iss savaal ka jawaab de sakte hai.

8 0
3 years ago
A metal ball of mass 2 kg is supported by a massless inextensible string, 12 cm long. A horizontal force displaces the ball by 3
Rudiy27

As it is given that 2 kg mass is suspended by 12 cm long thread and then a horizontal force is applied on it so that it remains in equilibrium at 30 degree angle

So here we can use force balance in X and Y directions

now for X direction or horizontal direction we can use

F = Tsin30

for vertical direction similarly we can say

mg = T cos30

so here we first divide the two equations

\frac{F}{mg} = \frac{sin 30}{cos 30}

\frac{F}{mg} = tan 30

F = mg tan30

now plug in all values in the above equation

F = 2 * 9.8 * tan30

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Part b)

now in order to find the tension in the thread we can use any above equation

F = T sin30

11.3 = T sin30

T = \frac{11.3}{sin30}

T = 22.6 N

so tension in the thread will be 22.6 N

4 0
3 years ago
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