Question

A heavy crate applies of 1500 N on a 25-m^2 piston . The smaller piston is 1/30 the size of the larger one . what force is needed to lif the crate

Answer 1

I don't know the name, but the opposite of gravity, if that helps!

Answer 2

Answer:

The force needed to lift the crate is 50 N

Explanation:

$P_{1} = \frac{F_{1}}{A_{1}} = \frac{1500N}{25 m^{2} } \\P_{1}= P_{2} \\P_{2} = \frac{F_{2}}{A_{2}}\\A_{2} = 25*\frac{1}{30} \\\frac{1500N}{25 m^{2} } =\frac{F_{2} }{\frac{25}{30}m^{2} }\\ F_{2}* 25 m^{2} = 1500 N *\frac{25}{30}m^{2}\\ F_{2}= \frac{1250 N*m^{2}}{25 m^{2}}\\ F_{2}= 50 N$