Answer:
<h2>e. 7.1 MN approx.</h2>
Explanation:
Step one:
given data
density of water= 1000kg/m^3
the dimension of the barge
width= 10m
length= 60m
depth of the boat in the water= 1.2m
Hence the volume occupied by the boat is
volume=10*60*1.2
volume= 720m^2
Step two:
Required is the weight of the barge
we can first find the mass using the relation
density = mass/volume
mass= density*volume
mass= 1000*720
mass= 720000kg
Step three:
Weight =mg
g=9.81m/s^2
W=720000*9.81
W=7063200N
divided by 10^6
W=7.06MN
W=7.1MN approx.
Answer:
Part a)

Part b)

Explanation:
As we know that electric force on electric charge is given as

here we have

E = 153 N/C
now force is given as

Gravitational force on electric charge near surface of earth is given as


now the ratio of two forces is given as


Part b)
Now the ball is balanced by the electric force and the force of gravity on it
so here we have



here we have

Answer: v = 
Explanation: q = magnitude of electronic charge = 
mass of an electronic charge =
V= potential difference = 4V
v = velocity of electron
by using the work- energy theorem which states that the kinetic energy of the the electron must equal the work done use in accelerating the electron.
kinetic energy =
, potential energy = qV
hence, 

There is not enough information to answer the question
The period of the wave is 25 s
<u>Explanation:</u>
To find the period of the wave, we have the formula
T= seconds/ no of cycle
T= 125/5
T= 25 s
The period of the wave is 25 s