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alexgriva [62]
3 years ago
14

Sound wave A is moving through a medium that is decreasing temperature.

Physics
2 answers:
lesya [120]3 years ago
4 0

Answer:

C they will slow down

Explanation:

Alla [95]3 years ago
3 0

Answer:

C, They will slow down.

Explanation:

Hope this helps :)

You might be interested in
In this formula, g=GM/R^2 , what do G ,m and R stand for?​
gtnhenbr [62]

Answer:

Explanation:

g means gravitation

G is universal gravitational constant

M = mass of the earth

R = radius of the earth

Hope this helps

plz mark as brainliets!!!!!!!!!

6 0
3 years ago
An air track car with a mass of 0.75 kg and a velocity of 8.5 m/s to the right collides elastically with a 0.65kg car moving to
Sunny_sXe [5.5K]
We can do this with the conservation of momentum. The fact it is elastic means no KE is lost so we don't have to worry about the loss due to sound energy etc.

Firstly, let's calculate the momentum of both objects using p=mv:

Object 1:
p = 0.75 x 8.5 = 6.375 kgm/s

Object 2 (we will make this one negative as it is travelling in the opposite direction):
p = 0.65 x -(7.2) = -4.68 kgm/s

Based on this we know that the momentum is going to be in the direction of object one, and will be 6.375-4.68=1.695 kgm/s

Substituting this into p=mv again:

1.695 = (0.75+0.65) x v
Note I assume here the objects stick together, it doesn't specify - it should!

1.695 = 1.4v
v=1.695/1.4 = 1.2 m/s to the right (to 2sf)
8 0
3 years ago
Which of the following statements cannot be supported by Kepler's laws of planetary motion? a. The distance of a planet around t
hodyreva [135]

i guess option (a)

is the right one

if it's correct

select me as brainliest

5 0
3 years ago
The length of a certain wire is kept same while its radius is doubled. what is the new resistivity of this wire?
anastassius [24]
The text does not specify whether the resistance R of the wire must be kept the same or not: here I assume R must be kept the same.

The relationship between the resistance and the resistivity of a wire is
\rho =  \frac{AR}{L}
where
\rho is the resistivity
A is the cross-sectional area
R is the resistance
L is the wire length

the cross-sectional area is given by
A=\pi r^2
where r is the radius of the wire. Substituting in the previous equation ,we find
\rho =  \frac{\pi r^2 R}{L}

For the new wire, the length L is kept the same (L'=L) while the radius is doubled (r'=2r), so the new resistivity is
\rho' =  \frac{\pi r'^2 R}{L'}= \frac{\pi (2r)^2 R}{L}=4  \frac{\pi r^2 R}{L}   = 4 \rho
Therefore, the new resistivity must be 4 times the original one.
5 0
3 years ago
Read 2 more answers
Please answer will give brainliest
laila [671]

3b. No

4a. 50N


I hope this helps


8 0
3 years ago
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