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Dominik [7]
3 years ago
6

How much heat is required to convert 500g of liquid water at 28°C into steam at 150 °C? Take the specific heat capacity of water

to be 4183 J/Kg °C and the latent heat of vaporization to be 2.26 × 10^6 J/Kg.
Physics
1 answer:
storchak [24]3 years ago
6 0

Answer:

Q = 1.404 × 10^(5) KJ

Explanation:

We are given:

Mass;m = 500 g = 0.5kg

Temperature 1;T1 = 28 °C

Temperature:T2 = 150 °C

Specific heat capacity;c_p = 4183 J/Kg °C

Latent heat of vaporization;L = 2.26 × 10^(6) J/Kg.

The heat energy needed is given by;

Q = sensible heat energy + Latent heat

Formula for sensible heat is;

Sensible heat energy = mc(t2 - t1)

Formula for Latent heat is ;

Latent heat = mL

Thus:

Q = mc(t2 - t1) + mL

Q = m[c(t2 - t1) + L]

Q = 0.5((4183(159 - 28) + (2.26 × 10^(6)))

Q = 1.404 × 10^(8) J = 1.404 × 10^(5) KJ

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Answer:

The energy consumption by toaster oven is 432 kJ and that of fluorescent light (CFL) bulb is 435 kJ.

Explanation:

Power of toaster oven, P = 1.2 kW

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Time, t' = 11 h = 39600 s

Energy used by fluorescent light (CFL) bulb is given by :

E'=P'\times t'\\\\E'=11\times 39600\\\\E'=435600\ J\\\\E'=435\ kJ

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Where do you find elements grouped that have the most similar physical and chemical properties?
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In a ballistic pendulum experiment, projectile 1 results in a maximum height h of the pendulum equal to 2.2 cm. a second project
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To explain it more in detailed: 


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KE = ½mV² or 


V = √(2KE/m) which shows you the other proportionality 


combining 


V = √(2mgh/m) = √(2gh) 


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