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Dominik [7]
3 years ago
6

How much heat is required to convert 500g of liquid water at 28°C into steam at 150 °C? Take the specific heat capacity of water

to be 4183 J/Kg °C and the latent heat of vaporization to be 2.26 × 10^6 J/Kg.
Physics
1 answer:
storchak [24]3 years ago
6 0

Answer:

Q = 1.404 × 10^(5) KJ

Explanation:

We are given:

Mass;m = 500 g = 0.5kg

Temperature 1;T1 = 28 °C

Temperature:T2 = 150 °C

Specific heat capacity;c_p = 4183 J/Kg °C

Latent heat of vaporization;L = 2.26 × 10^(6) J/Kg.

The heat energy needed is given by;

Q = sensible heat energy + Latent heat

Formula for sensible heat is;

Sensible heat energy = mc(t2 - t1)

Formula for Latent heat is ;

Latent heat = mL

Thus:

Q = mc(t2 - t1) + mL

Q = m[c(t2 - t1) + L]

Q = 0.5((4183(159 - 28) + (2.26 × 10^(6)))

Q = 1.404 × 10^(8) J = 1.404 × 10^(5) KJ

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Answer:

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Explanation:

From the question we are told that

       The  radius of the orbit is  r =  2.3 *10^{4} \ km  = 2.3  *10^{7} \ m

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The kinetic energy of the satellite is mathematically represented as

       KE  =  \frac{1}{2} * mv^2

where v is the speed of the satellite which is mathematically represented as

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=>  v^2  =  \frac{GM }{r}

substituting this into the equation

      KE  =  \frac{ 1}{2} *\frac{GMm}{r}

Now the gravitational force of the planet is mathematically represented as

      F_g  = \frac{GMm}{r^2}

Where M is the mass of the planet and  m is the mass of the satellite

 Now looking at the formula for KE we see that we can represent it as

     KE  =  \frac{ 1}{2} *[\frac{GMm}{r^2}] * r

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7 0
3 years ago
An overhead electric power line carries a maximum current of 125 A. What is the magnitude of the maximum magnetic field at a poi
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Answer:

B= 55.6×10^(-7) Tesla

Explanation:

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Answer:

4.5 s, 324 ft

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Substituting into the equation above, we find the corresponding time at which the object reaches the maximum height:

0=-32t+144\\t=\frac{144}{32}=4.5 s

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