Answer:
Q = 1.404 × 10^(5) KJ
Explanation:
We are given:
Mass;m = 500 g = 0.5kg
Temperature 1;T1 = 28 °C
Temperature:T2 = 150 °C
Specific heat capacity;c_p = 4183 J/Kg °C
Latent heat of vaporization;L = 2.26 × 10^(6) J/Kg.
The heat energy needed is given by;
Q = sensible heat energy + Latent heat
Formula for sensible heat is;
Sensible heat energy = mc(t2 - t1)
Formula for Latent heat is ;
Latent heat = mL
Thus:
Q = mc(t2 - t1) + mL
Q = m[c(t2 - t1) + L]
Q = 0.5((4183(159 - 28) + (2.26 × 10^(6)))
Q = 1.404 × 10^(8) J = 1.404 × 10^(5) KJ
