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kenny6666 [7]
3 years ago
7

What depends on public opinion and support?

Physics
1 answer:
Lelechka [254]3 years ago
6 0
Answer: A.) Regulations at a local level.
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What is the velocity of an object that has a mass of 2.5 kilogram and a momentum of 1,000 kg·m/sec?
nadezda [96]
V =  p / m

V =  1000 / 2.5

V = 400 m/s

hope this helps!
7 0
3 years ago
Can you solve it descriptively . thanks
Solnce55 [7]

Answer:

|M_y| = 170.82 \ N.mm

Explanation:

From the diagram affixed below completes the question

Now from the diagram; We need to resolve the force at point  A into (3) components ; i.e x.y. & z directions which are equivalent to F_x \ , F_y \ ,  F_z

So;

F_x = positive x axis

F_y = Negative y axis

F_z = positive z axis

Then;

|M_x| = F_y *27-F_z*11 = 77 ----- equation(1) \\ \\ |M_z| = F_y*4 - F_x*11 = 81 ---- equation (2) \\ \\ |M_y| = F_x *27 - F_z *4 = ?  ---- equation (3)

From equation (1); Let's make F_y the subject of the formula ; then :

F_y = \frac{77+11F_z}{27}

Substituting  the value for F_y into equation (2) ; we have:

(\frac{77+11F_z}{27})4-F_x*11=81 \\ \\ 11(\frac{7+F_z}{27} ) 4- F_x -11 =81 \\ \\ 28+4 F_z - 27F_x = \frac{81*27}{11} \\ \\ 4F_z - 27F_x = 198.82 -28 \\ \\ 4F_z - 27F_x = 170.82 \\ \\ Since  \ |M_y| = 4F_z-27F_x \\ \\ Then: \\ \\ \\ |M_y| = 170.82 \ N.mm

4 0
3 years ago
A car of mass 1000.0 kg is traveling along a level road at 100.0 km/h when its brakes are applied. Calculate the stopping distan
OleMash [197]

Explanation:

It is given that,

Mass of the car, m = 1000 kg

Speed of the car, v = 100 km/h = 27.77 m/s

The coefficient of kinetic friction of the tires, \mu_k=0.5

Let f is the net force acting on the body due to frictional force, such that,

-f=ma

a=\dfrac{-f}{m}

a=\dfrac{-\mu _k mg}{m}

a=\mu_k g

a=-0.5\times 9.8

a=-4.9\ m/s^2

We know that the acceleration of the car in calculus is given by :

v.dv=a.dx, x is the stopping distance

\int\limits^0_v {v.dv}=\int\limits^x_0 {a.dx}

\dfrac{v^2}{2}|_v^0=ax

0-(27.77)^2=-2\times 4.9x

On solving the above equation, we get, x = 78.69 meters

So, the stopping distance for the car is 78.69 meters. Hence, this is the required solution.

6 0
3 years ago
Write the equation of a wave traveling along the +x-axis with an amplitude of 0.02 m, a frequency of 440 Hz, and a speed of 330m
Airida [17]

The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)

<u>Explanation:</u>

Given data

Amplitude 0.02 m , Frequency= 440 Hz ,Speed = 330 m/s

The equation  format is written as,

y =   A   sin (       k        x  –   ω     t)

We need the value of  A, k, x -ω t

<u>1. Find the k value</u>

v     =  f ×λ

330 = 440×λ

   k = 2π×λ

k = 880 π /330  m-1

440 ×2π = w

<u>2. Find the ω  value</u>

f×2π =ω

ω = 880 π  s-1

<u>3. Find the A value</u>

we get A value from the given data

A = 0.02 m

By the formula,

y =   A   sin (       k        x  –   ω     t)

Substitute the values we get the equation,

y = 0.02 sin (880π/330 x – 880 πt)

The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)

8 0
3 years ago
What moves in and out of an open system like the human body? ​
HACTEHA [7]

Carbon dioxide because that's what we breath out?

3 0
3 years ago
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