V = p / m
V = 1000 / 2.5
V = 400 m/s
hope this helps!
Answer:

Explanation:
From the diagram affixed below completes the question
Now from the diagram; We need to resolve the force at point A into (3) components ; i.e x.y. & z directions which are equivalent to 
So;
= positive x axis
Negative y axis
= positive z axis
Then;

From equation (1); Let's make
the subject of the formula ; then :

Substituting the value for
into equation (2) ; we have:

Explanation:
It is given that,
Mass of the car, m = 1000 kg
Speed of the car, v = 100 km/h = 27.77 m/s
The coefficient of kinetic friction of the tires, 
Let f is the net force acting on the body due to frictional force, such that,






We know that the acceleration of the car in calculus is given by :
, x is the stopping distance



On solving the above equation, we get, x = 78.69 meters
So, the stopping distance for the car is 78.69 meters. Hence, this is the required solution.
The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)
<u>Explanation:</u>
Given data
Amplitude 0.02 m , Frequency= 440 Hz ,Speed = 330 m/s
The equation format is written as,
y = A sin ( k x – ω t)
We need the value of A, k, x -ω t
<u>1. Find the k value</u>
v = f ×λ
330 = 440×λ
k = 2π×λ
k = 880 π /330 m-1
440 ×2π = w
<u>2. Find the ω value</u>
f×2π =ω
ω
= 880 π s-1
<u>3. Find the A value</u>
we get A value from the given data
A = 0.02 m
By the formula,
y = A sin ( k x – ω t)
Substitute the values we get the equation,
y = 0.02 sin (880π/330 x – 880 πt)
The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)
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