Answer:
30%
Explanation:
<em>This is the chemical formula for zinc bromate: Zn(BrO₃)₂. Calculate the mass percent of oxygen in zinc bromate. Round your answer to the nearest percentage.</em>
Step 1: Determine the mass of 1 mole of Zn(BrO₃)₂
M(Zn(BrO₃)₂) = 1 × M(Zn) + 2 × M(Br) + 6 × M(O)
M(Zn(BrO₃)₂) = 1 × 65.38 g/mol + 2 × 79.90 g/mol + 6 × 16.00 g/mol
M(Zn(BrO₃)₂) = 321.18 g/mol
Step 2: Determine the mass of oxygen in 1 mole of Zn(BrO₃)₂
There are 6 moles of atoms of oxygen in 1 mole of Zn(BrO₃)₂.
6 × m(O) = 6 × 16.00 g = 96.00 g
Step 3: Calculate the mass percent of oxygen in Zn(BrO₃)₂
%O = mO/mZn(BrO₃)₂ × 100%
%O = 96.00 g/321.18 g × 100% ≈ 30%
Cells
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Answer:
To react with 0.5 moles of Zn 1 mole of HCl is required
Explanation:
Given data:
Number of moles of Zn = 0.50 mol
Number of moles of HCl = ?
Chemical equation:
Zn + 2HCl → H₂ + ZnCl₂
Now we will compare the moles of Zn and HCl through balance chemical equation.
Zn : HCl
1 : 2
0.50 : 2×0.5 = 1 mol
In order to react with 0.5 moles of zinc 1 mole of HCl is required.
Answer:
what you need to do is,
you take the relative atomic mass of each element and multiply it by the no of atoms it has. do this for all the elements present, and add the values. that's it!
Explanation:
try to do the last one by yourself, it is easy and you will be using the molecular/formula mass mostly everywhere in chemistry.
Answer:
The woodpecker population would start to decrease because of natural selection
Explanation: