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Vikentia [17]
3 years ago
14

Many fundraisers ask for donations using email and text messages. A paper describes an experiment to investigate whether the pro

portion of people who make a donation when asked for a donation by email is different from the proportion of people who make a donation when asked for a donation in a text message. In this experiment, 1.8% of those who received and opened an email request for a donation and 7.9% of those who received a text message asking for a donation actually made a donation. Assume that the people who received these requests were randomly assigned to one of the two groups (email or text message) and suppose that the given percentages are based on sample sizes of 2,000 (the actual sample sizes in the experiment were much larger). (Let p1 be the proportion who make a donation after receiving an email, and p2 be the proportion who make a donation after receiving a text message.)
The study described is an experiment with two treatments. What are the two treatments?
a. fundraisers
b. donations using text message
c. charitable giving
d. donations using email
e. deadlines
Mathematics
1 answer:
blagie [28]3 years ago
7 0

Answer:

b. donations using text message

d. donations using email

Step-by-step explanation:

From the question, it is clear that the people who received these requests were assigned to two groups and these 2 were assigned treatments of if they make donations after either receiving email or text messages after which their respective proportions p1 and p2 are determined.

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cluponka [151]

Answer:

this is my answer

Step-by-step explanation:

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5 0
3 years ago
Help algebra 2 please
kati45 [8]

Answer:

Step-by-step explanation:

(f*g)(x) = (-5x² + 2x + 7) (x +1)

          = x* (-5x² + 2x + 7) + 1*(-5x² + 2x + 7)

          = x*(-5x²) + x*2x + x*7 - 5x² + 2x + 7

        = -5x³ + 2x² + 7x - 5x² + 2x + 7

        = - 5x³ + <u>2x² -5x²</u>   <u>+ 7x + 2x </u>+7   {Combine like terms}

       =  -5x³ - 3x² + 9x + 7

4) (f*g)(x) = (x² + 2x + 4)(x - 2)

                = x*(x² + 2x + 4) - 2*(x² + 2x + 4)

                = x*x² + x*2x + x*4 - 2*x² - 2*2x -2* 4

                = x³ + 2x² + 4x  -2x² -4x - 8

                = x³ - 8

2) Speed=\dfrac{distance}{time}\\\\\\= \dfrac{d(h)}{t(h)}\\\\= \dfrac{2\sqrt{h}}{3\sqrt{4h}}=\dfrac{2*\sqrt{h}}{3*2\sqrt{h}}\\\\\\=\dfrac{1}{3}

1)d(h) = \sqrt{16h^{4}}=\sqrt{2*2*2*2*h*h*h*h}=2*2*h*h=4h^{2}\\\\\\t(h) = 3h^{4}-3h^{3}-5h^{2}= h^{2}(3h^{2}-3h - 5))\\\\Speed=\dfrac{4h^{2}}{h^{2}(3h^{2}-3h-5)}\\\\=\dfrac{4}{3h^{2}-3h-5}

7 0
3 years ago
If four out of ten people vote than a town with two hundred thousand people how many will vote
oksano4ka [1.4K]

Answer:

80,000 people will vote. I'm pretty sure

Step-by-step explanation:

You first divided 200,000 by 10 then multiply it by 4 and you get 80,000. You're welcome, if its right.

3 0
3 years ago
Read 2 more answers
Find the distance between points (2, 9) and (5, 4) to the nearest tenth​
Troyanec [42]

Answer:

Distance = 5.8

Step-by-step explanation:

d=\sqrt{(4-9)^{2} } { (5-2)} ^{2} \\

d = -5^{2}  + 3^{2}

d= 25 + 9

d= \sqrt{34}

distance = 5.8

3 0
3 years ago
Select the correct answer from the drop-down menu.
ELEN [110]

Missing term = –2xy

Solution:

Let us first find the quotient of -8x^2y^3 \div xy.

-8x^2y^3 \div xy=\frac{-8x^2y^3 }{xy}

                    =\frac{-8\times x\times x\times y\times y\times y}{xy}

Taking common term xy outside in the numerator.

                    =\frac{xy(-8\times x\times y\times y)}{xy}

Both xy in the numerator and denominator are cancelled.

                    =-8xy^2

Thus, the quotient of -8x^2y^3 \div xy is -8xy^2.

Given the quotient of -8x^2y^3 \div xy is same as the product  of 4xy and ____.

-8xy^2=4xy × missing term

Divide both sides by 4xy, we get

⇒ missing term = \frac{-8xy^2}{4xy}

Cancel the common terms in both numerator and denominator.

⇒ missing term = –2xy

Hence the missing term of the product is –2xy.

4 0
3 years ago
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