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Tresset [83]
3 years ago
15

Do 3-7 for me? It is science and i hate doing science hw.

Physics
1 answer:
shtirl [24]3 years ago
5 0
I can't bear to make you handle anything that makes you so uncomfortable. Please ask your Science teacher to contact me directly for the answers.
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A street lamp weighs 150N. It is supported by two wires that form an angle of 120° with each other. The tensions in each wire ar
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60

so you take 120÷2 wires

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What would the person’s mass be on the earth? Part B pls
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I hopes it helps

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What occurs when light changes direction after colliding with particles of matter
Slav-nsk [51]
Scattering occurs when light changes direction after colliding with particles of matter.
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3 years ago
a 75-kg refrigerator is located on the 70th floor of a skyscraper (300 meters above ground). what is the potential energy of the
mart [117]
Here, you can calculate it's potential energy with respect to ground.
We know, U = mgh
Here, m = 75 Kg
g = 9.8 m/s²       [ constant value for earth system ]
h = 300 m

Substitute their values into the expression:
U = 75 × 9.8  × 300
U = 220500 J

In short, Your Final Answer would be 220,500 J 

Hope this helps!
8 0
3 years ago
A particle leaves the origin with a speed of 3 106 m/s at 38 degrees to the positive x axis. It moves in a uniform electric fiel
Salsk061 [2.6K]

Answer:

If the particle is an electron E_y = 3.311 * 10^3 N/C

If the particle is a proton, E_y = 6.08 * 10^6 N/C

Explanation:

Initial speed at the origin, u = 3 * 10^6 m/s

\theta = 38^0 to +ve x-axis

The particle crosses the x-axis at , x = 1.5 cm = 0.015 m

The particle can either be an electron or a proton:

Mass of an electron, m_e = 9.1 * 10^{-31} kg

Mass of a proton, m_p = 1.67 * 10^{-27} kg

The electric field intensity along the positive y axis E_y, can be given by the formula:

E_y = \frac{2 m u^2 sin \theta cos \theta}{qx} \\

If the particle is an electron:

E_y = \frac{2 m_e u^2 sin \theta cos \theta}{qx} \\

E_y = \frac{2 * 9.1 * 10^{-31} * (3*10^6)^2 *(sin38)( cos38)}{1.6*10^{-19} * 0.015} \\

E_y = 3311.13 N/C\\E_y = 3.311 * 10^3 N/C

If the particle is a proton:

E_y = \frac{2 m_p u^2 sin \theta cos \theta}{qx} \\

E_y = \frac{2 * 1.67 * 10^{-27} * (3*10^6)^2 *(sin38)( cos38)}{1.6*10^{-19} * 0.015} \\

E_y = 6.08 * 10^6 N/C

8 0
3 years ago
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