Answer:
can u mark me brainliest
Explanation:
Following the Law
Matter cannot be created or destroyed in chemical reactions. This is the law of conservation of mass. In every chemical reaction, the same mass of matter must end up in the products as started in the reactants. Balanced chemical equations show that mass is conserved in chemical reactions
Atoms are considered the smallest particles of an element because they are the basic unit. They cannot be broken down into any smaller substance.
Answer: 2.04 moles
Explanation:
Mass of H2SO4 = 200g
RMM of H2SO4 = (2*1) + 32 + (16*4)
= 2 +32 +64 = 98
n = Mass concentration / RMM
n = 200/98
n = 2.04moles
Answer:
oxygen
Explanation:
because the 2nd shell is not complete which is suppose to be 8 and since oxygen is 8 it first shell is 2 which is complete and the second shell which is 6 is not complete because we all know that 2+6=8 but the standard shell is
K-2
L-8
M-8
Answer:
The correct answer is 89.6 L
Explanation:
We have the following chemical equation and the molar masses for the reaction:
3H₂(g) + N₂ --> 2 NH₃
6 g 28 g 34 g
That means that 3 moles of H₂ (6 g) reacts with 1 mol of N₂ (28 g) and gives 2 moles of NH₃ (34 g). In order to calculate how many liters of NH₃ result from the reaction of 12 grams of H₂ and 28 grams of N₂, we have to first figure out which reactant is the <em>limiting reactant</em>. According to the equation, if 6 grams of H₂ reacts with 28 g of N₂, and we have 12 grams:
6 g H₂------- 28 g N₂
12 g H₂-------- X = 12 g H₂ x 28 g N₂/6 g H₂ = 56 g N₂
We need 56 g of N₂ but we have 28 g of N₂, so <em>N₂ is the limiting reactant</em>. With the limiting reactant we can calculate the moles of product (NH₃) we will obtain:
We have 28 g N₂ -----> 28 g/14 g/mol = 2 moles N₂
1 mol N₂ ----------- 2 moles NH₃
2 mol N₂ --------- X = 2 mol N₂ x 2 moles NH₃/1 mol N₂ = 4 mol NH₃
Finally, we convert the moles of NH₃ to liters:
1 mol gas at STP = 22.4 L
Liters NH₃ obtained = 4 moles NH₃ x 22.4 L/1 mol = 89.6 L